我有一个Json,如下所示:-
{
"componentModelData": {
"modelNumber": "ABC",
"modelName": "",
"modelDescription": "",
"modelVendor": null,
"componentName": "HELO"
},
"revisionData": {
"revisionName": "rev12",
"revisionComment": "Comment",
"modifiedBy": "2323553"
},
"configData": [{"nodes":2085,"FxPOS-SX":16.5051,"FxPOS-SY":11.0479,"FxPOS-SZ":115.3421,"FxPOS-SXY":-13.8094,"FxPOS-SYZ":36.0105
},{"nodes":2085,"FxPOS-SX":16.5051,"FxPOS-SY":11.0479,"FxPOS-SZ":115.3421,"FxPOS-SXY":-13.8094,"FxPOS-SYZ":36.0105}]
}
DataMapping.java
@Getter
@Setter
@JsonSerialize
@NoArgsConstructor
@AllArgsConstructor
public class DataMapping implements Serializable {
/**
*
*/
private static final long serialVersionUID = -2635323042843403966L;
@JsonProperty("componentModelData")
@Valid
public ComponentModelDTO componentModelDTO;
@JsonProperty("revisionData")
@Valid
public RevisionDTO revisionDTO;
@JsonProperty("configData")
private List<Object> configData;
}
我想将configData列表转换为List<HashMap<String,Double>> list
,其中String是像'nodes,FxPOS-SX,FxPOS-SY'这样的键,而value是它们各自的值。
有人可以帮我实现这个目标吗?
答案 0 :(得分:2)
只需将List<Object>
替换为List<Map<String,Double>>
。杰克逊将为您完成艰苦的工作:
@JsonProperty("configData")
private List<Map<String, Double>> configData;