我正在使用Python处理一些JSON数据。基本上我有以下JSON数据
{
"users": [
{
"name": "John Doe",
"prefix": "[Test Account]",
"rank": "10"
},
{
"name": "Jane Doe",
"prefix": "[Test Account]",
"rank": "10"
}
]
}
我有一个循环,可以成功地循环使用Python中的用户。
for x in data["users"]:
if username == data["users"]["name"]:
print("true")
我只想获取name
值。在JS中,您可以这样做
data.users[x].name
但是您如何在Python中做到这一点。我尝试过类似的东西
data["users"][x]["name"]
和
data["users"[x]]["name"]
两个抛出错误。任何帮助将不胜感激。
答案 0 :(得分:4)
尝试一下:
data = {
"users": [
{
"name": "John Doe",
"prefix": "[Test Account]",
"rank": "10"
},
{
"name": "Jane Doe",
"prefix": "[Test Account]",
"rank": "10"
}
]
}
username = "John Doe"
for x in data["users"]:
if username == x["name"]:
print("true")
答案 1 :(得分:2)
我尝试了这个简单的例子,它可以工作:
array_of_integers = [[1,2,3],[2,4,5]....]
values = []
array_of_integers.each_with_index do |array, index|
values = if index.zero?
array
else
values & array
end
end
# `values` will be an array of common values
执行此操作时的错误消息是什么:
import json
j = '{"u":[{"a":1},{"a":2},{"a":3}]}'
d=json.loads(j)
print(d["u"][1]["a"])
# output: 2
?
答案 2 :(得分:1)
在以上答案中,您只需添加一个列表并获取所有名称。
data = {
"users": [
{
"name": "John Doe",
"prefix": "[Test Account]",
"rank": "10"
},
{
"name": "Jane Doe",
"prefix": "[Test Account]",
"rank": "10"
}
]
}
username = "John Doe"
names = []
for x in data["users"]:
names.append(x["name"])
>>names
['John Doe', 'Jane Doe']
答案 3 :(得分:0)
data = {
"users": [
{
"name": "John Doe",
"prefix": "[Test Account]",
"rank": "10"
},
{
"name": "Jane Doe",
"prefix": "[Test Account]",
"rank": "10"
}
]
}
for x in data['users']:
print(x['name'])