我想将对象转换为数组格式。 输入对象是
{
"index": {
"0": 40,
"1": 242
},
"TID": {
"0": "11",
"1": "22"
},
"DepartureCity": {
"0": "MCI",
"1": "CVG"
},
"ArrivalCity": {
"0": "SFB",
"1": "LAS"
},
"Price": {
"0": 90,
"1": 98
}
}
预期输出为
[
{
"index": 40,
"TID": "11",
"DepartureCity": "MCI",
"ArrivalCity": "SFB",
"Price": 90
},
{
"index": 242,
"TID": "22",
"DepartureCity": "CVG",
"ArrivalCity": "LAS",
"Price": 98
}
]
我尝试使用for循环,但是它变得越来越复杂。如果有人可以帮助我,那将非常感激。
答案 0 :(得分:4)
这是一种const postItems = this.props.posts.map(post => (
<div key={post.id} className="row">
<div className="container">
<h3>{post.title}</h3>
<p>{post.body}</p>
<button
onClick={() =>this.editPost(post)}
className="btn btn-primary">
Edit
</button>
<button
onClick={() =>this.deletePost(post.id)}
className="btn btn-danger">
Delete
</button>
</div>
</div>
))
方法
lodash
_.merge([], ..._.map(obj, (v, k) => _.mapValues(v, ev=> ({[k]:ev}))))
let inputObj = {
"index": {
"0": 40,
"1": 242
},
"TID": {
"0": "11",
"1": "22"
},
"DepartureCity": {
"0": "MCI",
"1": "CVG"
},
"ArrivalCity": {
"0": "SFB",
"1": "LAS"
},
"Price": {
"0": 90,
"1": 98
}
};
let res = _.merge([], ..._.map(inputObj, (v, k) => _.mapValues(v, ev=> ({[k] :ev}))));
console.log(res);
答案 1 :(得分:2)
尝试reduce
-将entries
放入对象数组,遍历内部对象的每个值:
const input={"index":{"0":40,"1":242},"TID":{"0":"11","1":"22"},"DepartureCity":{"0":"MCI","1":"CVG"},"ArrivalCity":{"0":"SFB","1":"LAS"},"Price":{"0":90,"1":98}}
const output = Object.entries(input).reduce((a, [key, obj]) => {
Object.values(obj).forEach((val, i) => {
if (!a[i]) a[i] = {};
a[i][key] = val;
});
return a;
}, []);
console.log(output);
答案 2 :(得分:1)
您可以将Object.keys
与reduce
组合使用
let object = { "index": { "0": 40, "1": 242 }, "TID": { "0": "11", "1": "22" }, "DepartureCity": { "0": "MCI", "1": "CVG" }, "ArrivalCity": { "0": "SFB", "1": "LAS" }, "Price": { "0": 90, "1": 98 } }
result = Object.keys(object['index']).map(function(key){
return Object.keys(object).reduce(function(obj, item){
obj[item] = object[item][key];
return obj;
}, {});
});
console.log(result);
答案 3 :(得分:0)
您可以将内部值映射到相应的索引。
var data = { index: { 0: 40, 1: 242 }, TID: { 0: "11", 1: "22" }, DepartureCity: { 0: "MCI", 1: "CVG" }, ArrivalCity: { 0: "SFB", 1: "LAS" }, Price: { 0: 90, 1: 98 } },
result = Object
.entries(data)
.reduce(
(r, [k, o]) => Object
.entries(o)
.map(([i, v]) => Object.assign(r[i] || {}, { [k]: v })),
[]
);
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
答案 4 :(得分:0)
使用lodash,您只需要使用_.reduce()
和_.forEach()
方法,如下所示:
const result = _.reduce(Object.entries(object), function(a, [key, obj]){
_.forEach(Object.values(obj), function(val, i){
if (!a[i]) a[i] = {};
a[i][key] = val;
});
return a;
}, []);
演示:
const object = {
"index": {
"0": 40,
"1": 242
},
"TID": {
"0": "11",
"1": "22"
},
"DepartureCity": {
"0": "MCI",
"1": "CVG"
},
"ArrivalCity": {
"0": "SFB",
"1": "LAS"
},
"Price": {
"0": 90,
"1": 98
}
};
const result = _.reduce(Object.entries(object), function(a, [key, obj]){
_.forEach(Object.values(obj), function(val, i){
if (!a[i]) a[i] = {};
a[i][key] = val;
});
return a;
}, []);
console.log(result);
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.10/lodash.core.js"></script>