我想将PathFindExtensionW
api的输出分配给WCHAR数组。此api返回LPWSTR指针。我搜索并发现了将LPWSTR分配给WCHAR数组的方法,如下所示:
WCHAR array[100] = PathFindExtensionW(,,,)
但是它对我不起作用,并且我收到此错误:
表达式必须是可修改的左值
我正在使用VS2012。我的代码如下:
#include <windows.h>
#include <iostream>
#include "Shlwapi.h"
#pragma comment(lib,"shlwapi.lib")
void main(int argc, char *argv[]){
int iToSizeB = 0;
iToSizeB = MultiByteToWideChar(CP_UTF8, 0, argv[1], -1 , NULL, 0);
WCHAR lpFileAddress[260] = {0};
MultiByteToWideChar(CP_UTF8, 0, argv[1], -1, lpFileAddress, iToSizeB);
WCHAR lpDotPosition[260] = {0};
//this line must be correct but I receive error
lpDotPosition = PathFindExtensionW(lpFileAddress);
int iToSizeW = 0;
iToSizeW = WideCharToMultiByte(CP_UTF8, 0, lpDotPosition, -1, NULL, 0, NULL, NULL);
CHAR lpExtension[260] = {0};
WideCharToMultiByte(CP_UTF8, 0, lpDotPosition, -1, lpExtension, iToSizeW, NULL, NULL);
printf("the format is:\n");
printf(lpExtension);
printf("\n");
getchar();
}
这是怎么了?
感谢您的解决方案。
答案 0 :(得分:0)
不能通过为数组分配指针来填充数组。您必须复制数据,例如使用lstrcpynW()
或类似功能:
LPCWSTR lpDotPosition = PathFindExtensionW(lpFileAddress);
WCHAR lpExtensionW[MAX_PATH] = {0};
lstrncpy(lpExtensionW, lpDotPosition, MAX_PATH);
但是,PathFindExtension()
只是在您传入的字符串缓冲区内返回一个指针,因此无需分配扩展名的单独副本,数据已预先分配,返回的指针将只要输入字符串有效,就保持有效:
#include <windows.h>
#include <iostream>
#include <Shlwapi.h>
#pragma comment(lib, "shlwapi.lib")
int main(int argc, char *argv[])
{
WCHAR lpFileAddress[MAX_PATH] = {0};
int iToSizeB = MultiByteToWideChar(CP_UTF8, 0, argv[1], -1, lpFileAddress, MAX_PATH);
LPCWSTR lpDotPosition = PathFindExtensionW(lpFileAddress);
CHAR lpExtension[MAX_PATH] = {0};
int iToSizeW = WideCharToMultiByte(CP_UTF8, 0, lpDotPosition, -1, lpExtension, MAX_PATH, NULL, NULL);
printf("the format is:\n%s\n", lpExtension);
getchar();
return 0;
}
另一方面,无需仅使用MultiByteToWideChar()
和WideCharToMultiByte()
来搜索char
字符串,而可以使用PathFindExtensionA()
:
#include <windows.h>
#include <iostream>
#include <Shlwapi.h>
#pragma comment(lib, "shlwapi.lib")
int main(int argc, char *argv[])
{
LPCSTR lpExtension = PathFindExtensionA(argv[1]);
printf("the format is:\n%s\n", lpExtension);
getchar();
return 0;
}