这是在$ .each中获取数组值的方式。我正在获取每个模型和数量的价值。 reserved_qty是我表中的值。这是我的查询。
$sql = $conn->prepare("SELECT *, COUNT(backup_sales.model_id) as ReservedQTY FROM backup_sales
LEFT JOIN product_model ON backup_sales.model_id = product_model.model_id
LEFT JOIN brand ON brand.brand_id = product_model.brand_id
LEFT JOIN client ON client.client_id =backup_sales.client_id
LEFT JOIN company ON company.company_id = client.company_id
WHERE backup_sales.po_ID = '".$_GET['po_ID']."'
GROUP BY backup_sales.model_id, backup_sales.client_id");
//Reserved Qtys Function
$('input[name^="reserved_qty"]', '#tblEdit').each(function(){
obj = {};
if (this.className == "" && this.value == "0"){
return this.value;
}
else
{
obj["model"] = this.className;
obj["reserved_qty"] = this.value;
}
my_arr.push(obj);
});
//Input Qtys Function
$('input[name^="quantity"]', '#tblEdit').each(function(){
obj = {};
if (this.className == "" && this.value == "0"){
return this.value;
}
else
{
obj["model_id"] = this.className;
obj["input_quantity"] = this.value;
}
dataObs.push(obj);
});
这是我显示每个值并分配2个数组的方式。
$.each(my_arr, function(index, value){
$.each(dataObs, function(subIndex, val){
console.log(value);
console.log(val);
});
});
我希望我的价值成为
{model: "1", reserved_qty: "4"}
{model_id: "1", input_quantity: "4"}
{model_id: "3", input_quantity: "3"}
{model: "3", reserved_qty: "3"}
{model: "4", reserved_qty: "3"}
{model_id: "4", input_quantity: "3"}
到目前为止,我的价值是继续获得这些价值
{model: "1", reserved_qty: "4"}
{model_id: "3", input_quantity: "3"}
{model: "1", reserved_qty: "4"}
{model_id: "4", input_quantity: "3"}
{model: "3", reserved_qty: "3"}
{model_id: "1", input_quantity: "4"}
{model: "3", reserved_qty: "3"}
{model_id: "4", input_quantity: "3"}
答案 0 :(得分:0)
不确定我是否正确理解了您的问题,但是由于您有嵌套循环,因此需要检查内部循环的每次迭代,以确保model
与model_id
匹配。否则,它将为表单中的每个条目输出每个数据库行(您的外部循环)。
类似这样的东西:
$.each(my_arr, function(index, value){
$.each(dataObs, function(subIndex, val){
if (value.model == val.model_id) { // you need to check model vs model_id here
console.log(value);
console.log(val);
}
});