<li>未从Firebase填充名称

Question

<div data-role="content" data-theme="" id="main" role="main">
		
		<div data-position="fixed" data-role="footer" data-theme="a">
			<div data-role="navbar">
				<ul>
					<li>
						<a class="font-new ui-nodisc-icon loader-class" data-textonly="false" data-textvisible="true" data-iconpos="notext" onclick="$(location).attr('href', 'iprefs.php')" data-icon="home" href="#"></a>
					</li>
					<li>
						<a data-icon="flat-menu" class="font-new ui-btn-active loader-class" data-textonly="false" data-textvisible="true" onclick="location.reload();"></a>
					</li>
					<li>
						<a data-icon="flat-settings" class="font-new loader-class" data-textonly="false" data-textvisible="true" onclick="$(location).attr('href', 'settings.php')"></a>
					</li>
				</ul>
			</div>
		</div>
	</div>
	<script>$('#main').append('<ul data-filter-reveal="true" data-filter="true" data-role="listview" data-inset="true" id="applist"></ul>');</script>

您好，我有这个应用程序，我试图用我的Firebase数据库中的名称填充li，但是它创建了li，但其中没有任何名称

var list = $('#appList');
    var url = firebase.database().ref('/');
    url.on('value', getAppList);
    function getAppList(packages){
        var fbAppList = packages.val();
        var childRef = url.child('/');
        childRef.once('value', function(snapshot){
            snapshot.forEach(function(child){
                var $name = child.val().name;
            });
        
            $.each(fbAppList, function(i, app) {
                console.log(name);
                $('#applist').append($('<li>').append('<a href="">'+ name +'</a>'));
                $('#applist').listview("refresh");      
            });
        });      
    };

Answer 1

如何将代码$（'

'）更改为$（'li'） 参见https://developer.android.com/guide/topics/resources/drawable-resource#LayerList