Question

我想按部门和日期创建工作时间轴。我有一个SQL喜欢 select department,sum(workinghours),date group by department,date. 然后我写一个数据透视

select * from(
     select department,sum(workinghours) as hours,date group by department,date
        )as RC
    PIVOT
    (
        sum(hours) for date 
    )as P

但是这返回很多空值。所以我将枢纽更新为

select * from(
         select department,sum(workinghours) as hours,date group by department,date
            )as RC
        PIVOT
        (
            (case when sum(hours) is null then 0 else sum(hours) end) for date 
        )as P

然后它有错误。我不明白为什么，有人可以帮忙吗？

Answer 1

您需要用null中的某些特定值替换sum。由于我替换了0而不是null：

create table #t
(
Id int identity (1,1),
Department varchar (100),
WorkingHours int  ,
Date datetime
)

Insert into #t (Department,WorkingHours,Date)
Select '1','10',GETDATE ()-1

Insert into #t (Department,WorkingHours,Date)
Select '1','20',GETDATE ()-1
Insert into #t (Department,WorkingHours,Date)
Select '1',null,GETDATE ()

select * from #t

select * from(
         select department,sum(ISNULL(workinghours,0)) as hours,
         cast (Year(date) as varchar) date 
         from #t
         group by department,date
            )as RC
        PIVOT
        (
            sum(hours ) for date  IN ([2018])
        )as P

Answer 2

请尝试下面的例子求和：

select * from(
         select department,sum(workinghours) as hours,date group by department,date
            )as RC
        PIVOT
        (
            sum(case when hours is null then 0 else hours end) for date 
        )as P

如何在透视图中使用案例

2 个答案: