我想使用lapply函数从列表中提取嵌入在元素内的元素。原始列表包含碰巧是数组的元素,R包geomorph中的gpagen函数弹出一个新列表,其中每个元素都包含一个嵌入其中的元素,我想将这些嵌入的元素定向到一个新对象。 / p>
输入示例:
>unaligned_coords
$individual1
, , rep1
[,1] [,2] [,3]
[1,] 58.81923 2.452332 273.2005
[2,] 68.24838 -4.298481 271.2884
[3,] 69.58006 -1.127088 270.0316
, , rep2
[,1] [,2] [,3]
[1,] 58.82360 2.485687 273.1929
[2,] 68.14501 -4.233420 271.3564
[3,] 69.02335 -0.875766 270.4671
$individual2
, , rep1
[,1] [,2] [,3]
[1,] 58.64723 -1.7827113 271.4866
[2,] 69.53938 -7.0807052 274.4347
[3,] 72.35068 0.1114307 272.1112
, , rep2
[,1] [,2] [,3]
[1,] 58.63091 -1.7735939 271.4576
[2,] 68.78160 -6.9430161 274.1252
[3,] 73.07706 0.3313497 272.1727
...
在输入示例中使用lapply:
aligned_coords <- lapply(unaligned_coords, gpagen)
输出,其中元素(坐标)嵌入元素(个体)中:
>aligned_coords$individual1$coords
, , rep1
[,1] [,2] [,3]
[1,] -0.1838745 -0.002361134 0.001343360
[2,] 0.1717784 -0.065992358 -0.003245113
[3,] 0.1701612 0.025533125 -0.068783434
, , rep2
[,1] [,2] [,3]
[1,] -0.1844239 0.00147890 0.0001282347
[2,] 0.1846240 -0.07485290 -0.0031490047
[3,] 0.1681969 0.02331805 -0.0627923402
>aligned_coords$individual2$coords
, , rep1
[,1] [,2] [,3]
[1,] -0.1439503 0.007217439 0.04066458
[2,] 0.1154014 -0.009312094 -0.10422833
[3,] 0.1673553 0.117909836 0.03056590
, , rep2
[,1] [,2] [,3]
[1,] -0.14248417 0.004972831 0.03475940
[2,] 0.09739824 -0.008022416 -0.09583761
[3,] 0.17839128 0.122139269 0.03668812
所需的输出示例:
>aligned_coords
$individual1
, , rep1
[,1] [,2] [,3]
[1,] -0.1838745 -0.002361134 0.001343360
[2,] 0.1717784 -0.065992358 -0.003245113
[3,] 0.1701612 0.025533125 -0.068783434
, , rep2
[,1] [,2] [,3]
[1,] -0.1844239 0.00147890 0.0001282347
[2,] 0.1846240 -0.07485290 -0.0031490047
[3,] 0.1681969 0.02331805 -0.0627923402
$individual2
, , rep1
[,1] [,2] [,3]
[1,] -0.1439503 0.007217439 0.04066458
[2,] 0.1154014 -0.009312094 -0.10422833
[3,] 0.1673553 0.117909836 0.03056590
, , rep2
[,1] [,2] [,3]
[1,] -0.14248417 0.004972831 0.03475940
[2,] 0.09739824 -0.008022416 -0.09583761
[3,] 0.17839128 0.122139269 0.03668812
...
lapply可能吗?我尝试了以下方法:
aligned_coords <- lapply(unaligned_coords, gpagen)$coords
但是我得到了
>aligned_coords
NULL
答案 0 :(得分:0)
在应用coords
函数之后,我们可以使用匿名函数调用提取gpagen
library(geomorph)
lapply(unaligned_coords, function(x) gpagen(x)$coords)
set.seed(24)
unaligned_coords <- list(individual1 = array(rnorm(3 * 3 * 2, 60),
dim = c(3, 3, 2), dimnames = list(NULL, NULL, c("rep1", "rep2"))),
individual2 = array(rnorm(3 * 3 * 2, 60), dim = c(3, 3, 2),
dimnames = list(NULL, NULL, c("rep1", "rep2")) ) )