Question

T-SQL：
下面是我需要在col上应用逐行过滤器的表。我的标准是Val应当为：0 AND（1或1.1）AND 2

原始表格是

name   val
aaa    0
aaa    1
aaa    1.1
aaa    2
bbb    0
bbb    2
ccc    0
ccc    1
ccc    2

预期结果将

name   val
aaa     0
aaa     1
aaa     1.1
aaa     2
ccc     0
ccc     1
ccc     2

任何人都可以提出解决方案。我正在尝试Where子句，但无法在where子句中提供条件。感谢任何帮助

Answer 1

满足条件时，以下内容将返回该组中的所有行：

DECLARE @test TABLE(
      name varchar(10) NOT NULL
    , value varchar(10) NOT NULL
);

INSERT INTO @test(name, value)
VALUES
     ('aaa', '0')
    ,('aaa', '1')
    ,('aaa', '1.1')
    ,('aaa', '2')
    ,('bbb', '0')
    ,('bbb', '2')
    ,('ccc', '0')
    ,('ccc', '1')
    ,('ccc', '2');

SELECT a.name, a.value
FROM @test a
CROSS APPLY(SELECT COUNT(*) FROM @test b WHERE b.name = a.name AND value IN('0', '2')) AS b(cnt)
CROSS APPLY(SELECT COUNT(*) FROM @test b WHERE b.name = a.name AND value IN('1', '1.1')) AS c(cnt)
WHERE b.cnt = 2 AND c.cnt >= 1;

Answer 2

将这3个条件指定为cte并连接到原始表。匹配的行应为3

; with 
-- your table
tbl as    
(
    select  name   = 'aaa',    val = 0    union all
    select  name   = 'aaa ',   val = 1    union all
    select  name   = 'aaa',    val = 1.1  union all
    select  name   = 'aaa',    val = 2    union all
    select  name   = 'bbb',    val = 0    union all
    select  name   = 'bbb',    val = 2    union all
    select  name   = 'ccc',    val = 0    union all
    select  name   = 'ccc',    val = 1    union all
    select  name   = 'ccc',    val = 2
),
--  your condition
val as
(
    select  val1 = 0, val2 = 0    union all
    select  val1 = 1, val2 = 1.1  union all
    select  val1 = 2, val2 = 2
),
cte_name as
(
    select  t.name
    from    tbl t
            inner join val v    on  t.val   = v.val1
                                or  t.val   = v.val2
    group by name
    having count(distinct v.val1) = 3   -- matching rows should be 3
) 
-- the query
select  t.*
from    tbl t
        inner join cte_name n   on  t.name  = n.name

Answer 3

另一个版本：

DECLARE @test TABLE(
      name varchar(10) NOT NULL
    , value decimal(5,1) NOT NULL
);

INSERT INTO @test(name, value)
VALUES
     ('aaa', 0)
    ,('aaa', 1)
    ,('aaa', 1.1)
    ,('aaa', 2)
    ,('bbb', 0)
    ,('bbb', 2)
    ,('ccc', 0)
    ,('ccc', 1)
    ,('ccc', 2);

select a.name, a.value 
from @test a
join (
    select name, 
        sum(case when value IN(0,2) then 1 else 0 end) as c02, 
        sum(case when value IN(1,1.1) then 1 else 0 end) as c1 
    from @test group by name
    ) g on g.name=a.name and c02=2 and c1>=1

SQL：按行值过滤列

3 个答案: