原始代码：
$sql .= "
LEFT OUTER JOIN";
在“加入”之后点击“输入”，我想要的是
$sql .= "
LEFT OUTER JOIN
(cursor)";
我得到的是
$sql .= "
LEFT OUTER JOIN
(cursor)";
如何解决？
编辑：而且，即使我的标签设置没有说要这样做，Eclipse也会插入4个空格而不是一个标签。
答案 0 :(得分：0)
这并不是一个完美的解决方案，但是会使事情变得更好（在Eclipse PDT 6.2中进行了测试）：
在偏好设置下，转到import java.util.*;
public class Main {
public static void main(String[] args) {
normalizeText();
obify("THISISSOMEREALLYGREATTEXT" );
}
// Part 1 Normalized Method to convert all letter to uppercase and removing all special characters and placing it into String codey.
public static String normalizeText (){
Scanner sc = new Scanner( System.in );
String normText;
System.out.println("Please input text to encrypt");
normText = sc.nextLine();
System.out.println(normText.replaceAll(" ","").replaceAll("[^a-zA-Z ]", "").toUpperCase());
return normText;
}
//This method will take in the Normalized text and insert a capital O and B in-front of every vowel and return the text
private static String obify (String input) {
String obifiledInput = input;
for (int i = 0; i < input.length(); i++) {
if (input.contains( Character.toString( input.charAt( i ) ) )) {
obifiledInput = obifiledInput + "OB" + Character.toString( input.charAt( i ) );
} else {
obifiledInput = obifiledInput + Character.toString( input.charAt( i ) );
}
System.out.println(obifiledInput);
}
return obifiledInput;
}
}
并选中PHP > Editor > Typing