我正在尝试向我的mysql数据库发送值,我是php / bootstrap编程的新手,并且我已经尝试了所有方法,但是大多数指南超出了我的理解。请按照正确的路径引导我,因此在按钮上单击按钮将更新特定的数据库。
点击按钮的操作如下: 在“卸载”按钮上,单击它将发送更新数据库,例如
UPDATE activate =“ No”从软件WHERE uid(or id)=“单击按钮所在行的相同ID”“ [我知道此mysql查询错误]
这是我的代码:
<!DOCTYPE html>
<html lang="en">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<meta charset="utf-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<meta name="viewport" content="width=device-width, initial-scale=1">
<title>Control Panel</title>
<!-- Bootstrap -->
<link href="css/bootstrap.min.css" rel="stylesheet">
<!-- Font Awesome -->
<link href="css/font-awesome.min.css" rel="stylesheet">
<!-- NProgress -->
<link href="css/nprogress.css" rel="stylesheet">
<!-- iCheck -->
<link href="css/green.css" rel="stylesheet">
<!-- Datatables -->
<link href="css/dataTables.bootstrap.min.css" rel="stylesheet">
<link href="css/buttons.bootstrap.min.css" rel="stylesheet">
<link href="css/fixedHeader.bootstrap.min.css" rel="stylesheet">
<link href="css/responsive.bootstrap.min.css" rel="stylesheet">
<link href="css/scroller.bootstrap.min.css" rel="stylesheet">
<!-- Custom Theme Style -->
<link href="css/custom.min.css" rel="stylesheet">
</head>
<body class="nav-md">
<div class="container body">
<div class="main_container">
<div class="col-md-12 left_col">
<div class="left_col scroll-view">
<div class="col-md-12 col-sm-12 col-xs-12">
<div class="x_panel">
<div class="x_content">
<table id="datatable-buttons" class="table table-striped table-bordered">
<thead>
<tr>
<th>S/N</th>
<th>Date</th>
<th>IP Address</th>
<th>UID</th>
<th>Activation</th>
<th>Command</th>
</tr>
</thead>
<tbody>
<?php
$count_rows = 0;
include 'database_connection.php';
$sql = "SELECT `date`, `ip`, `id`, `activate` FROM `software`";
$result = $conn->query($sql);
while ($row = mysqli_fetch_array($result)):
$count_rows++;
?>
<tr>
<td><?php echo $count_rows ?></td>
<td><?php echo $row['date']; ?></td>
<td><?php echo $row['ip']; ?></td>
<td><?php echo $row['id']; ?></td>
<td><?php echo $row['activate']; ?> <td><button type="button" id="btn-uninstall" class="btn btn-danger btn-xs">Uninstall</button> <button type="button" id="btn-install" class="btn btn-success btn-xs">Install</button> <button type="button" id="btn-upgrade" class="btn btn-warning btn-xs">Upgrade</button></td>
</tr>
<?php endwhile; ?>
</tbody>
</table>
<!-- jQuery -->
<script src="js/jquery.min.js"></script>
<!-- Bootstrap -->
<script src="js/bootstrap.min.js"></script>
<!-- FastClick -->
<script src="js/fastclick.js"></script>
<!-- NProgress -->
<script src="js/nprogress.js"></script>
<!-- iCheck -->
<script src="js/icheck.min.js"></script>
<!-- Datatables -->
<script src="js/jquery.dataTables.min.js"></script>
<script src="js/dataTables.bootstrap.min.js"></script>
<script src="js/dataTables.buttons.min.js"></script>
<script src="js/buttons.bootstrap.min.js"></script>
<script src="js/buttons.flash.min.js"></script>
<script src="js/buttons.html5.min.js"></script>
<script src="js/buttons.print.min.js"></script>
<script src="js/dataTables.fixedHeader.min.js"></script>
<script src="js/dataTables.keyTable.min.js"></script>
<script src="js/dataTables.responsive.min.js"></script>
<script src="js/responsive.bootstrap.js"></script>
<script src="js/dataTables.scroller.min.js"></script>
<script src="js/jszip.min.js"></script>
<script src="js/pdfmake.min.js"></script>
<script src="js/vfs_fonts.js"></script>
<!-- Custom Theme Scripts -->
<script src="js/custom.min.js"></script>
</body>
</html>
以下是该页面的屏幕截图:https://image.ibb.co/eToeaz/Capture.png
答案 0 :(得分:0)
如果您希望它立即发生,请使用AJAX将请求发送到php服务器,有关更多信息,请参见https://www.w3schools.com/php/php_ajax_database.asp。
如果您要重定向,请使用
$conn = new mysqli("DBservername", "DBusername", "DBpassword", "DBname");
if ($conn->connect_errno) {
$errormsg = ("Database Connection failed: " . $conn->connect_error );
return $errormsg;
}
$res=mysqli_query($conn, "SELECT * FROM 'table' WHERE 'something'");
$row=$res->fetch_array();
$count = mysqli_num_rows($res); // if fetch correct it returns must be 1 row
mysqli_close($conn);
if( $count == 1 ) etc
发送查询,更新,删除等
$sql = "DELETE FROM 'table' WHERE 'something';
mysqli_query($conn,$sql);
粗糙和糟糕的php代码,但应该可以。
在我了解您的实际要求后进行编辑: 从数据库呈现结果时,锚定每个按钮以重定向到页面/ update / {rowid}或/update.php?id={rowid}
,并在该链接中使用条件等执行查询。
答案 1 :(得分:0)
您可以通过此代码向服务器发送请求。
$con = new mysqli_connect("servername", "username", "password", "name");
if(!$con)
{
die("DB CONNECTION ERROR");
}
$result=mysqli_query($con, "SELECT * FROM 'table' WHERE 'something'");
$row=$result->fetch_array();
$count = mysqli_num_rows($result);
mysqli_close($con);
if( $count == 1 )