Question

id birth
-----------------------------
1 1079280000 (2004-03-15) 
2 987264000  (2001-04-15)
3 1042560000 (2003-01-15)

如何为sql转换为birth时间戳为1300118400（2011-03-15）;

<?php
  $now = strtotime('2011-03-04');// today's timestamp
  $sql = "SELECT * FROM member 
  WHERE birth(1079280000  convert to 1300118400) > $now";
?>

Results
id   birth 
---------------
1 1079280000 (2004-03-15) 
2 987264000  (2001-04-15)

我需要将birth转换为当前年份的生日timestamp。

Answer 1

无子选择解决方案：

SELECT
  id,
  UNIX_TIMESTAMP(
    FROM_UNIXTIME(birth) +
    INTERVAL (YEAR(CURDATE()) - YEAR(FROM_UNIXTIME(birth))) YEAR
  ) AS birthday
FROM member
WHERE NOW() < FROM_UNIXTIME(birth) +
              INTERVAL (YEAR(CURDATE()) - YEAR(FROM_UNIXTIME(birth))) YEAR

不确定MySQL如何使用派生表（ab），但上述查询可能更具可读性，如果重写如下：

/* Stage 3. Filtering out past birthdays and
   converting datetime dates to unix timestamps. */
SELECT
  id,
  UNIX_TIMESTAMP(birthday_date) AS birthday
FROM (
  /* Stage 2. Getting this year birthdays */
  SELECT
    id,
    birth_date + INTERVAL (YEAR(CURDATE()) - YEAR(birth_date)) AS YEAR birthday_date
  FROM (
    /* Stage 1. Converting unix timestamps to datetime values. */
    SELECT
      id,
      FROM_UNIXTIME(birth) AS birth_date
    FROM member
  ) m
) m
WHERE NOW() < birthday_date

Answer 2

这已在下面的帖子中解释

How to convert date to timestamp in PHP?

Answer 3

SQL有一个DATEPART函数（http://msdn.microsoft.com/en-us/library/ms174420.aspx），您可以使用它来获取出生日期的日期和月份，并在比较中使用它们在PHP中获得今天的日期和月份。可能有更好的方法，但这种方式至少应该起作用。：）

这当然假设您的日期存储为数据库中的日期而不是整数。：）

Answer 4

如果我理解，如果是mysql：

SELECT day(FROM_UNIXTIME(birth)) as birthday
FROM member 
WHERE birth > $now

如何从字段时间戳将出生日期转换为当前年份的生日？

4 个答案: