我有两个清单。
第一个列表包含语言,并包含约30000
个项目。
['es','de', 'ita', ....]
第二个列表包含大约二十种语言代码,如下所示:
['eng', 'ar', 'fr', 'ch', 'jp', 'ita' .... ]
我想做的是搜索并查看第1
本书是否与代码19
有关(1是第一本书的索引),如果找到,请打印第二个列表中的代码索引
import csv
book_language_list = []
with open('language_table_for_search.csv', 'r') as rf:
reader = csv.reader(rf, delimiter=',')
for row in reader:
book_language_list.append(row[2])
book_language_distinc = []
with open('language_codes.csv', 'r') as rf:
reader = csv.reader(rf, delimiter=',')
for row in reader:
book_language_distinc.append(row[1])
for i in range(0, len(book_language_list)):
if any(book_language_list[i] in s for s in book_language_distinc):
# print the book id=i has language=(found language index)
答案 0 :(得分:4)
一种方法是使用文档中的索引函数:
此方法返回找到的对象的索引,否则引发 指示找不到值的异常。
赞:
books = ['es', 'de', 'ita', 'eng']
codes = ['eng', 'ar', 'fr', 'ch', 'jp', 'ita']
for book in books:
try:
ii = codes.index(book)
print(book, ii)
except ValueError:
pass
输出:
ita 5
eng 0
如果按书有多种语言,并且每本书都由一个列表表示,则可以这样操作:
books = [['es'], ['de'], ['ita', 'ch'], ['eng']]
codes = {code: ii for ii, code in enumerate(['eng', 'ar', 'fr', 'ch', 'jp', 'ita'])}
for book in books:
book_codes = [(lang, codes[lang]) for lang in book if lang in codes]
if book_codes:
print(book_codes)
输出:
[('ita', 5), ('ch', 3)]
[('eng', 0)]
该行:
codes = {code: ii for ii, code in enumerate(['eng', 'ar', 'fr', 'ch', 'jp', 'ita'])}
创建一个字典,其中键是语言代码,而值是列表中的索引。最后,
book_codes = [(lang, codes[lang]) for lang in book if lang in codes]
获取代码中的书籍语言,如果列表不为空,则打印结果。
答案 1 :(得分:2)
简单解决方案:
使用set()
set & set
返回两个集合的交集。
示例:
books = ['es', 'de', 'ita', 'eng']
codes = ['eng', 'ar', 'fr', 'ch', 'jp', 'ita']
for r in set(books)&set(codes):
print(r, codes.index(r))
返回:
eng 0
ita 5
答案 2 :(得分:0)
使用enumerate
解决了以下问题:
for i in range(0, len(book_language_list)):
print("book {} has language {}={}".format(i, book_language_list[i], [j for j, s in enumerate(book_language_distinc) if book_language_list[i] in s]))
输出:
book 27279 has language 'us'=[5]