Question

我试图在Selenium中制作多个标签，并同时在每个标签上打开一个页面。这是代码。

CHROME_DRIVER_PATH = "C:/chromedriver.exe"

from selenium import webdriver
import threading
driver = webdriver.Chrome(CHROME_DRIVER_PATH)

links = ["https://www.google.com/",
         "https://stackoverflow.com/",
         "https://www.reddit.com/",
         "https://edition.cnn.com/"]

def open_page(url, tab_index):
    driver.switch_to_window(handles[tab_index])
    driver.get(url)
    return

# open a blank tab for every link in the list
for link in range(len(links)-1 ): # 1 less because first tab is already opened
    driver.execute_script("window.open();")

handles = driver.window_handles # get handles

all_threads = []
for i in range(0, len(links)):
    current_thread = threading.Thread(target=open_page, args=(links[i], i,))
    all_threads.append(current_thread)
    current_thread.start()

for thr in all_threads:
    thr.join()

执行没有错误，据我所知，从逻辑上讲应该可以正常工作。但是，该程序的效果并不像我想象的那样。它一次只打开一页，有时甚至不切换选项卡...是否有我在代码中没有意识到的问题，或者Selenium无法使用线程？

Answer 1

无需切换到新窗口即可获取URL，您可以在下面尝试在新标签页中依次打开每个URL：

links = ["https://www.google.com/",
         "https://stackoverflow.com/",
         "https://www.reddit.com/",
         "https://edition.cnn.com/"]

# Open all URLs in new tabs
for link in links:
    driver.execute_script("window.open('{}');".format(link))

# Closing main (empty) tab
driver.close()

现在，您可以照常处理（如果需要）driver.window_handles中的所有窗口

线程和硒

1 个答案: