Question

我要转换

E =[1,6,1,7,2,3,2,6,3,2,3,8,4,5,4,7,5,4,5,9,6,1,6,7,6,2,7,1,7,6,7,4,8,9,8,3,9,8,9,5,]

进入

E = [{1,6},{1,7},{2,3},{2,6},{3,2},{3,8},{4,5},{4,7},{5,4},{5,9},{6,1},{6,7},{6,2},{7,1},{7,6},{7,4},{8,9},{8,3},{9,8},{9,5}

但我明白了

E=[[{1, 6}], [{1, 7}], [{2, 3}], [{2, 6}], [{2, 3}], [{8, 3}], [{4, 5}], [{4, 7}], [{4, 5}], [{9, 5}], [{1, 6}], [{6, 7}], [{2, 6}], [{1, 7}], [{6, 7}], [{4, 7}], [{8, 9}], [{8, 3}], [{8, 9}], [{9, 5}]]

取而代之的是

，集{。}中的顺序也被混淆了（不保留顺序）。

为什么会这样，我该如何解决？

我的代码是：

def convert_to_set(x):
    sets = []
    l = len(x)
    for i in range(0,l,2):
        set1 = []      
        set1.append({x[i],x[i+1]})
        sets.append(set1)
    return sets

Answer 1

如果要保留订单，则需要从set切换到tuple。这样很容易做到：

list(zip(E[::2], E[1::2]))

那给你：

[(1, 6),
 (1, 7),
 (2, 3),
 (2, 6),
 (3, 2),
...

Answer 2

以下是一个选项：

function check_match($string) {
    if (preg_match('/^([a-z]{2,})(?:\1)+(.*)$/', $string, $matches)) {
        return strlen($matches[2]) == 0 || $matches[2] == substr($matches[1], 0, strlen($matches[2])) ? $matches[1] : false;
    }
    return false;

}

foreach (array("abca", "abcabcab", "abcabcabcabc", "ababcababc", "aabbaabb", "aabaab", "aabaabd", "abcd", "aabcaabc", "abcabca") as $str) {
    if ($pattern = check_match($str))
        echo "$str matched $pattern\n";
    else 
        echo "no pattern for $str\n";
}

此外，集合是无序的，因此您无法保留顺序。

（Python）将整数列表转换为元组/集合会更改整数的位置

2 个答案: