Question

例如：

<FlatList data={ this.state.foods, this.state.trees }
          renderItem={({item}) => <View><Text>{item.food}</Text><Text>{item.tree}</Text></View>
/>

只要我具有相同的密钥（id），是否有可能这样工作？

this.state.foods：

[{
  "id": "1",
  "food":"chicken",
  "cal":"1000",
}]

this.state.trees：

[{
  "id": "1",
  "tree":"pine",
  "size":"10",
}]

编辑：

    render(){
      const {trees, foods} = this.state
const combinedArray = trees.map(tree => Object.assign(tree, foods.find(food => food.id == tree.id)));
      return(




    componentDidUpdate(prevProps, prevState) {
      if (!prevState.foods) {

        fetch('https://www.example.com/React/food.php')
         .then((response) => response.json())
         .then((responseJson) => {
           this.setState({
             isLoading: false,
             foods:  responseJson.map(item => ({ ...item, progress: new Animated.Value(0), unprogress: new Animated.Value(1) }))

             }, function() {

           });
         })
         .catch((error) => {
           //console.error(error);
         });
         fetch('https://www.example.com/React/tree.php')
            .then((response) => response.json())
            .then((responseJson) => {
              this.setState({
                isLoading: false,
                trees:  responseJson
                }, function() {

              });
            })
            .catch((error) => {
              //console.error(error);
            });
}
}

Answer 1

您需要为array data提供一个Flatlist。

您可以根据id对对象进行分组并使用它们

const {trees, foods} = this.state
const combinedArray = trees.map(tree => Object.assign(tree, foods.find(food => food.id == tree.id)));

，然后在combinedArray中使用Flatlist

如果您的state最初是undefined或null，则需要添加

constructor(props) {
    super(props)
    this.state = {
      trees: [],
      foods: []
    }
   }

您的班级组成部分。

FlatList的数据中可能有多个参数吗？

1 个答案: