Question

基本上，我想以某种方式模拟友谊继承，这种限制只能在某种方法内部发生。

所以本质上，这就是我想要的

class A; // Forward declaration
class Base{
   friend class A; // friend declaration so that A is able to see protected methods

   protected:
   virtual void method() {// some definition, might also be pure virtual}

}

class Derived : public Base{
     A aObj;
     void method(){//override the one in base and also gain access to aObj private members.}
     public:
     //public interface
} 


class A {
    int var;
    friend void Base::method(); 
    public:
      // public interface
}

反正有实现这一目标的方法吗？

Answer 1

怎么样

class Base {
   friend class A; 
   protected:
   virtual void method() = 0;
   std::tuple<int> GetAProperties(const A& a) {     
        // You can change the tuple params
        // as per your requirement.
        return std::make_tuple(a.var);
   }
}

class Derived : public Base {
    A aObj;
    void method() override {
        auto objProperties = GetAProperties(aObj);
    }
}

Answer 2

您可以在A中获得指向private的Base成员的指针，然后将这些成员指针传递给Derived：

class A; // Forward declaration
class Base{
   friend class A; // friend declaration so that A is able to see protected methods

   private:
   void method(A&);
   virtual void do_method(A& a,int A::* var) {// some definition, might also be pure virtual
     (a.*var)++;
   }

};
class A{
    int var;
    friend void Base::method(A&);
};
class Derived : public Base{
     A aObj;
     virtual void do_method(A& a,int A::* var) {// some definition, might also be pure virtual
     a.*var+=2;
   }
     public:
     //public interface
};

void Base::method(A& a){
       do_method(a,&A::var);
   }

注意：不要在关键关卡上使用它！

重写是另一个类的朋友的虚拟受保护方法

2 个答案: