使用函数和循环拼接字符串值并存储为数组

Question

我有一个数字列表，该数字是使用循环的字符串值，我想将此字符串拆分为数组中不同的变量，长度3的第一个，长度7的6和长度3的最后一个。这可以通过函数和循环来完成。

Answer 1

我们可以做这样的事情：

 
let str = '000111111122222223333333444444455555556666666mmmm';

// Defines the lengths we're using
let lengths = [3,7,7,7,7,7,7,3];

let index = 0;

let result = lengths.reduce((acc,n) => {
    acc.push(str.slice(index, index += n));
    return acc;
} , [])

console.log(result);

Answer 2

您可以映射子字符串。

var str = '000111111122222223333333444444455555556666666mmmm',
    lengths = [3, 7, 7, 7, 7, 7, 7, 3],
    result = lengths.map((i => l => str.slice(i, i += l))(0));

console.log(result);

Answer 3

这是一种方法：

let theArray = document.getElementById('theArray');
let theVariable = document.getElementById('theVariable');
let targetString = "122333444455555666666";
let dataSizes = [1, 2, 3, 4, 5, 6];
var result = [];
var pos = 0;
dataSizes.forEach( (size) => {
    result.push(targetString.substr(pos, size));
    pos += size;
});
theArray.textContent = result.toString();
let [one, two, three, four, five, six] = result;
theVariables.textContent = `${one}-${two}-${three}-${four}-${five}-${six}`;

Answer 4

一种通用的方法是，如果您想要一个变量，则可以使用subStringLengthMaps键：-

let str="abcdefghijklmnopqrstu";
let  subStringLengthMap={a:3, b:7, c:7 , d:3};

//making pure funciton
var getStrings = function(str, subStringLengthMap){
  let result =[];
  Object.keys(subStringLengthMap).forEach(function(key){
  let temp = str.slice(0, subStringLengthMap[key]);
  result.push(temp);
    str = str.replace(temp,'');
  })

  return result;

}

//call the function
console.log(getStrings(str, subStringLengthMap))