我的ksh脚本如下。
if [ `uname` == "AIX" ]; then
export LIBPATH_BKP_$$=$LIBPATH
# Trap so that it will return the original library path when script exits
trap 1 2 3 9 15 "export LIBPATH=$LIBPATH_BKP_$$; unset LIBPATH_BKP_$$"
export LIBPATH=/usr/mqm/lib:$LIBPATH
else # All else will be either Linux or Solaris which uses LD_LIBRARY_PATH
export LD_LIBRARY_PATH_BKP_$$=$LD_LIBRARY_PATH
# Trap so that it will return the original library path when script exits
trap 1 2 3 9 15 "export LD_LIBRARY_PATH=$LD_LIBRARY_PATH_BKP_$$; unset LD_LIBRARY_PATH_BKP_$$"
export LD_LIBRARY_PATH=/usr/mqm/lib:$LD_LIBRARY_PATH_BKP_$$
fi
当我执行它时说
tdestop.ksh [52]:陷阱:export LD_LIBRARY_PATH = 49648;未设置LD_LIBRARY_PATH_BKP_49648:错误陷阱
tdestop.ksh-是脚本名称及其在第52行的提示错误。
问题是什么是陷阱?这是怎么了?我不是这方面的专家。抱歉,这个问题真的是新手。
谢谢, 德维雅
答案 0 :(得分:1)
语法是:
trap action signals...
例如
trap 'echo "I caught something"' HUP INT TERM
您已经翻转了动作和信号的顺序,这就是ksh
抱怨的原因。您应该改用:
trap "export LIBPATH=$LIBPATH_BKP_$$; unset LIBPATH_BKP_$$" 1 2 3 9 15