Question

我正在尝试在Jenkins的常规DSL中拆分URL http://localhost:8081/artifactory/api/storage/myrepo/sub1/file.zip。它是单行字符串。但是下面的代码不起作用

String[] arr= string_var.split('/');  
String[] arr=string_var.split('\\/');

它不拆分它，并以arr [0]返回自身。我不确定这是否是错误。请告诉我是否有其他方法可以从URL字符串中获取“ sub1”。

Answer 1

确定要正确执行DSL脚本吗？常规代码看起来还可以。尝试跳过声明类型

def url_str = 'http://localhost:8081/artifactory/api/storage/myrepo/sub1/file.zip'
def sub = url_str.split('/')[-2]
println(sub)

一行：

println('http://localhost:8081/artifactory/api/storage/myrepo/sub1/file.zip'.split('/')[-2])

不拆分，索引：

def url_str = 'http://localhost:8081/artifactory/api/storage/myrepo/sub1/file.zip'
int[] indexes = url_str.findIndexValues {it == "/"}
println url_str.substring(indexes[-2] + 1, indexes[-1])

Answer 2

尝试将您的代码包含在DSL语言的“脚本”标签中，如以下代码所示：

pipeline {
  agent any
  stages {
    stage('Test') {
      steps {
        script {
          def string_var = "http://localhost:8081/artifactory/api/storage/myrepo/sub1/file.zip"
          String[] arr= string_var.split('/');
          println "${arr[0]}"
        }
      }
    }
  }
}

执行上面的代码，我在控制台上得到以下结果：

[Pipeline] {
[Pipeline] stage
[Pipeline] { (Test)
[Pipeline] script
[Pipeline] {
[Pipeline] echo
http:
[Pipeline] }
[Pipeline] // script
[Pipeline] }
[Pipeline] // stage
[Pipeline] }
[Pipeline] // node
[Pipeline] End of Pipeline

因此，提供预期的“ http：”字符串

获取字符串'sub1'（正则表达式）的另一种Groovy方法：

String s = "http://localhost:8081/artifactory/api/storage/myrepo/sub1/file.zip"

def match = s =~ /(sub1)/
if (match.size() > 0) { // If url 's' contains the expected string 'sub1'
  println match[0][1]
  // Or do something with the match
}

无法在Groovy DSL中分割字符串，并且没有多行

2 个答案: