Question

使用下表，如何将Guid值插入表的guidField中。使用以下常规代码将导致以下错误“因为：在这种情况下不允许使用名称“ B551F2C8”。生成的向导是B551F2C8-8380-491B-A51F-436E51CDD08F。也许Guid中的“-”是问题所在。有什么想法吗？

SQL表

create table tblTest  
(
  guidField  uniqueidentifier,
  strField  varchar(50),
  dateField smalldatetime
)

代码块

UUID uuid = UUID.randomUUID()
long lTimeStamp = d.getTime();
String tableInsert = "INSERT INTO tblTest (guidField,strField,dateField)" +
                                  " VALUES ("   + uuid +
                                            "," + 'test' +
                                            "," + lTimeStamp +
                                            ")";
sql.execute(tableInsert);

Answer 1

UUID uuid = UUID.randomUUID()
//long lTimeStamp = d.getTime();
String tableInsert = "INSERT INTO tblTest (guidField,strField,dateField)" +
                              " VALUES ('" + uuid + "'"
                                        ",'test'" +
                                        ", getdate()"
                                        ")";
sql.execute(tableInsert);

在应用程序中需要向导吗？如果没有，请让SQL Server为您生成一个：

String tableInsert = "INSERT INTO tblTest (guidField,strField,dateField)" +
                              " VALUES (newid()"
                                        ",'test'" +
                                        ", getdate()"
                                        ")";
sql.execute(tableInsert);

将GUID插入SQL表Uniqueidentifier字段-Groovy

1 个答案: