SQL语句org.h2.jdbc.JdbcSQLException中的语法错误:

时间:2018-08-17 10:50:07

标签: spring-data-jpa h2

嗨,这是我的资料库

@Repository
interface GuestRepository : JpaRepository<Guest, Long> {

@Query("from Guests g where g.date>=:fromDate and g.date<=:toDate ",nativeQuery = true)
fun findInPeriod(
        @Param("fromDate") fromDate: Date
        , @Param("toDate") toDate: Date
        , pageRequest: Pageable
): Page<Guest>

}      

这是我的客人对象

@Entity
@Table(name = "Guests")
data class Guest(
    @Id
    @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "guest_seq")
    @SequenceGenerator(name = "guest_seq", sequenceName = "guest_seq", allocationSize = 1)
    val id: Long=0
    ,
    @Column(length = 50, unique = true)
    @NotNull
    @Size(min = 4, max = 50)
    val userName: String="username"
    , val firstName: String?=null
    , val lastName: String?=null
    ,
    @Temporal(TemporalType.TIMESTAMP)
    @NotNull
    val date: Date=Date()
)

我使用spring和h2,但是当我运行我的应用程序时,它向我显示此错误消息

org.h2.jdbc.JdbcSQLException: Syntax error in SQL statement "FROM GUESTS G WHERE[*] G.DATE>=? AND G.DATE<=?  LIMIT ? "; expected "(, USE, RIGHT, LEFT, FULL, INNER, JOIN, CROSS, NATURAL, ,, SELECT"; SQL statement:    

1 个答案:

答案 0 :(得分:0)

使用nativeQuery = true告诉Spring Data JDBC将您的查询视为本机(即SQL)查询。

但是您提供的查询不是合法的SQL。 它看起来非常类似于HQL,它是JPQL的一种特定于Hibernate的方言。

要解决此问题,请删除nativeQuery = true部分或使用SQL