Question

如果c.forename列为空或空白，我必须从c.known_as获取姓氏。当使用

语句时，我实现了这一点

CASE 
   WHEN IND.KNOWN_AS IS NULL OR ind.KNOWN_AS='' 
    THEN ind.FORENAMES 
   ELSE ind.KNOWN_AS 
END AS 'Known As'

我的问题是在“姓氏”列中，我的名字像Jhon Smith，在这里我只想提取John，下面是我要实现的示例

Desire output   c.forename
John             Mr John
Jhon            Jhon Smith
blank            Jo
blank              J

因此，基本上只需要跳过'Mr'即可使用姓氏，第二次只需要使用超过2个字符的姓氏即可。

我当前的查询是：

 Select ind.FORENAMES,
        ind.KNOWN_AS,
        case when (known_as is null or known_as = '' ) and charindex(' ', forenames) > 2 
          then substring(forenames, 1, charindex(' ', forenames) - 1) end as FORENAMES2,
        output 
from individual ind 
join member m on m.individual_ref=ind.individual_ref 
  and m.MEMBERSHIP_NO in ('001','002','003','004','005','006','007') 
where m.member_status=33

Answer 1

您可以使用以下case when语句来验证您的条件：

对于SQL Server：

case when (c.known_as is null or c.known_as = '' )
      and charindex(' ', c.forename) > 3 then substring(c.forename, 1, charindex(' ', c.forename) - 1) end

对于MySQL：

case when (c.known_as is null or c.known_as = '' )
      and locate(' ', c.forename) > 3 then substring(c.forename, 1, locate(' ', c.forename) - 1) end

很少的解释：如果名字必须超过2个字符，则意味着名字空间必须至少出现在索引4处。而且条件是关于：locate(' ', c.forename) > 3或substring(' ', c.forename) > 3 < / p>

注意

您必须首先在Mr列中清除Mrs，Ms和c.forename的所有出现，像这样（MySQL和SQL Server的语法）：

replace(replace(replace(c.forename, 'Mrs ', ''),  'Mr ', ''), 'Ms ', '')

您必须将其包含在查询中，例如：

Select FORENAMES,
       KNOWN_AS,
       case when (known_as is null or known_as = '' ) and charindex(' ', FORENAMES2) > 2 
         then substring(FORENAMES2, 1, charindex(' ', FORENAMES2) - 1) end as FORENAMES2,
       output
from (
    Select ind.FORENAMES,
           ind.KNOWN_AS,
           replace(replace(replace(ind.FORENAMES, 'Mrs ', ''),  'Mr ', ''), 'Ms ', '') FORENAMES2,
           output
    from individual ind 
    join member m on m.individual_ref = ind.individual_ref 
    where m.member_status=33
      and m.MEMBERSHIP_NO in ('001','002','003','004','005','006','007')
)

Answer 2

尝试一下：

DECLARE @DataSource TABLE
(
    [name] VARCHAR(32)
);

INSERT INTO @DataSource ([name])
VALUES (' Mr John ')
      ,('Jhon Smith')
      ,('  Jo  ')
      ,('  J  ');

WITH SanitizeDataSoruce ([name], [name_reversed]) AS
(
    SELECT LTRIM(RTRIM([name]))
          ,REVERSE(LTRIM(RTRIM([name])))
    FROM @DataSource
)
SELECT [name]
      ,CASE 
            WHEN CHARINDEX(' ', [name]) > 1 THEN REVERSE(SUBSTRING([name_reversed], 0, CHARINDEX(' ', [name_reversed])))
            ELSE ''
       END
FROM SanitizeDataSoruce;

如果字符大于2个字母，则提取姓名

2 个答案: