Question

说我有一个数组，

this.list = [
  {id:1, task: 'circle',   janstartdate: '2017-01-01', febstartdate: '2017-02-01' },
  {id:2, task: 'square',   janstartdate: '2017-01-06', febstartdate: '2017-02-11' },
  {id:3, task: 'triangle', janstartdate: '2017-01-10', febstartdate: '2017-02-21' }  
]

是否可以使用Javascript获得一个类似于下面的新列表的新数组？

我不确定下面的代码片段是否正确；但基本上，我想按“ janstartdate”列重新组合原始数组，然后按新数组中同一级别的“ febstartdate”进行重新组合。

这可能吗？

输出为：

newlist = [
{
 month: 
  {'january': 
   [ 
     2017-01-01: { id:1, task: 'circle'},
     2017-01-06: { id:2, task: 'square'},
     2017-01-10: { id:3, task: 'triangle'}
   ],
 month: 
  {'february': 
   [ 
     2017-02-01: { id:1, task: 'circle'},
     2017-02-11: { id:2, task: 'square'},
     2017-02-21: { id:3, task: 'triangle'}
   ],
  }

Answer 1

您可以做这样的事情

list = [
  {id: 1,task: 'circle',janstartdate: '2017-01-01',febstartdate: '2017-02-01'},
  {id: 2,task: 'square',janstartdate: '2017-01-06',febstartdate: '2017-02-11'},
  {id: 3,task: 'triangle',janstartdate: '2017-01-10',febstartdate: '2017-02-21'}
]

newList = {
  january: {},
  february: {}
}

list.map(item => {
  newList.january[item.janstartdate] = {
    id: item.id,
    task: item.task
  }
  newList.february[item.febstartdate] = {
    id: item.id,
    task: item.task
  }
})

console.log(newList)

在january中使用february和list可能有助于减少重复

像这样：

list = [
  {id:1, task: 'circle', january: '2017-01-01', february: '2017-02-01' },
  {id:2, task: 'square', january: '2017-01-06', february: '2017-02-11' },
  {id:3, task: 'triangle', january: '2017-01-10', february: '2017-02-21' }  
]

newList = {}

months = ["january", "february"]

list.map(item => {
  for (let month of months) {
    if (!newList[month]) {
      newList[month] = {}
    }
    newList[month][item[month]] = {
      id: item.id,
      task: item.task
    }
  }
})

console.log(newList)

仅当每个数据都是唯一的时，这些方法才有效；如果它们不是唯一的，则仅保留最后一个数据。

Javascript根据特定的列属性将数组重塑为新数组

1 个答案: