我有两个多维数组。如果键相同,那么我想得到总和,我该怎么做。 一个是-
Array
(
[2018-08-02] => Array
(
[male] => 1
[female] => 0
)
[2018-08-07] => Array
(
[male] => 1
[female] => 0
)
[2018-08-09] => Array
(
[male] => 1
[female] => 5
)
)
第二个是- 一个是-
Array
(
[2018-08-02] => Array
(
[male] => 3
[female] => 4
)
[2018-08-07] => Array
(
[male] => 1
[female] => 5
)
[2018-08-06] => Array
(
[male] => 2
[female] => 3
)
)
所以我的结果是
Array
(
[2018-08-02] => Array
(
[male] => 4
[female] => 4
)
[2018-08-07] => Array
(
[male] => 2
[female] => 5
)
[2018-08-09] => Array
(
[male] => 1
[female] => 5
)
[2018-08-06] => Array
(
[male] => 2
[female] => 3
)
)
代码为
foreach ($reportlist as $reportlists){
$daterep=$reportlists['act_date'];
$arr[$daterep]['male']=$reportlists['male_cnt'];
$arr[$daterep]['female']=$reportlists['female_cnt'];
}
foreach ($ureportlist as $ureportlists){
$daterep=$rueportlists['act_date'];
$arr2[$daterep]['male']=$reportlists['male_cnt'];
$arr2[$daterep]['female']=$reportlists['female_cnt'];
}
答案 0 :(得分:2)
这是您的代码,
<?php
function pr($arr = [])
{
echo "<pre>";
print_r($arr);
echo "</pre>";
}
$arr1 = array
(
"2018-08-02" => array
(
"male" => 1,
"female" => 0,
),
"2018-08-07" => array
(
"male" => 1,
"female" => 0,
),
"2018-08-09" => array
(
"male" => 1,
"female" => 5,
),
);
$arr2 = array
(
"2018-08-02" => array
(
"male" => 3,
"female" => 4,
),
"2018-08-07" => array
(
"male" => 1,
"female" => 5,
),
"2018-08-06" => array
(
"male" => 2,
"female" => 3,
),
);
function custom_function($arr){
$retArr = array();
foreach ($arr as $child) { // arr1, arr2
foreach ($child as $key => $value) { // traversing through keys
foreach($value as $k => $v){
if (isset($retArr[$key][$k])) { // if key is set then add
$retArr[$key][$k] += $v;
} else {
$retArr[$key][$k] = $v; // else initiate
}
}
}
}
return $retArr;
}
$result=custom_function(array($arr1,$arr2));
pr($result);die;
这是您的工作code
答案 1 :(得分:0)
您可以使用array_intersect_key()检查是否有匹配的结果要添加它们。 例如,假设您的两个数组是$ array1和$ array2。然后您可以使用
$result = array_intersect_key($array1, $array2);
这将返回数组中的交集。因此,您可以确定需要添加哪些键(以您的情况为准,哪些日期)。
答案 2 :(得分:0)
您可以使用array_merge_recursive来加入错误,然后对结果数组中的子数组求和
$res = array_merge_recursive($arr1, $arr2);
foreach($res as &$date) {
foreach($date as &$sex) {
$sex = array_sum((array) $sex);
}
}
print_r($res);
答案 3 :(得分:0)
您只需要迭代第二个数组并确定第一个数组中是否存在日期键。 isset()
是运行该检查的最好/最有效的方法。
如果第2个数组中的日期尚不存在,则可以将行的数据存储到第1个数组中。如果日期在第一个数组中已经存在,那么您将需要(分别)添加男性和女性的值。
代码:(Demo)
$array1 = [
'2018-08-02' => ['male' => 1, 'female' => 0],
'2018-08-07' => ['male' => 1, 'female' => 0],
'2018-08-09' => ['male' => 1, 'female' => 5]
];
$array2 = [
'2018-08-02' => ['male' => 3, 'female' => 4],
'2018-08-07' => ['male' => 1, 'female' => 5],
'2018-08-06' => ['male' => 2, 'female' => 3]
];
foreach ($array2 as $date => $row) {
if (!isset($array1[$date])) {
$array1[$date] = $row; // store row data with unique date
} else {
$array1[$date]['male'] += $row['male']; // perform addition
$array1[$date]['female'] += $row['female']; // perform addition
}
}
// ksort($array1); if you want to order by date
var_export($array1);
输出:
array (
'2018-08-02' =>
array (
'male' => 4,
'female' => 4,
),
'2018-08-07' =>
array (
'male' => 2,
'female' => 5,
),
'2018-08-09' =>
array (
'male' => 1,
'female' => 5,
),
'2018-08-06' =>
array (
'male' => 2,
'female' => 3,
),
)