插入带有子类型列的表中:类型继承,面向对象的SQL

时间:2018-08-17 08:23:29

标签: sql oracle oracle11g

当我尝试将数据插入下表时。

create table Policies of policy_t(
pid primary key,
inscar references Cars
)nested table claims store as  claims_ntable;

使用以下查询,

insert into policies
        select policy_t ('PLC1234','12 Mar 2017','12 Mar 2018',REF(C),175000,claim_t('CLAIM1234567','12 Feb 2017','56000',REF(T)))
        from cars C,customer T
        where C.regno = 'CAB3233' and T.cid = '123ABC'

我得到以下错误

Error starting at line : 1 in command -
insert into policies
select policy_t ('PLC1234','12 Mar 2017','12 Mar    2018',REF(C),175000,claim_t('CLAIM1234567','12 Feb 2017','56000',REF(T)))
from cars C,customer T
where C.regno = 'CAB3233' and T.cid = '123ABC'
Error at Command Line : 3 Column : 25
Error report -
SQL Error: ORA-00942: table or view does not exist
00942. 00000 -  "table or view does not exist"
*Cause:    
*Action:

如何在此表中插入数据?

其他相关的对象类型和表,

客户对象类型

create type Customer_t as object(
cid char(6),
cusname varchar(15),
birthdate date,
phone char(10),
address varchar(50)
);

客户表

create table Customers of customer_t(
cid primary key
);

声明对象类型

create type claim_t as object(
claimno char(12),
cdate date,
amount number(8,2),
claimant ref customer_t
);

声明嵌套表

create type Claim_ntab is table of claim_t;

汽车对象类型

create type Car_t as object(
regno char(9),
make varchar(12),
model varchar(10),
mdate date,
owner ref customer_t,
value number(8,2)
);

汽车桌子

create table Cars of car_t(
regno primary key,
owner references Customers
);

策略对象类型

create type policy_t as object(
pid char(7),      
sdate date,
edate date,
inscar ref car_t,
premium number(6,2),
claims claim_ntab
)

政策表

create table Policies of policy_t(
pid primary key,
inscar references Cars
)nested table claims store as  claims_ntable;

3 个答案:

答案 0 :(得分:1)

更正表名(customer / customers)后,下一个问题是customers.claimsclaim_ntab,但是您试图插入{{1} } 进去。试试这个:

claim_t

编辑:我使用对象引用将您的insert into policies select policy_t ( 'PLC1234' , date '2017-03-12' , date '2018-03-12' , ref(ca) , 175000 , claim_ntab(claim_t ( 'CLAIM1234567' , date '2017-02-12' , '56000' , ref(cu) ) ) ) from cars ca join customers cu on ref(cu) = ca.owner where ca.regno = 'CAB3233' and cu.cid = '123ABC' 子句联接更改为ANSI样式。老实说,我以前没有使用过这种语法,而且我怀疑很少有人使用过,因此需要进行一些测试。

答案 1 :(得分:0)

您将表格命名为Customers,请注意复数形式。

所以改变

from cars C,customer T

from cars C,customers T

甚至更好,无论如何,请使用显式JOIN语法重写它。

答案 2 :(得分:0)

INSERT INTO _table1_ (_field1_, _field2_, _field3_)字段名称,而不是值 SELECT _field1_, _field2_, _field3_ FROM _table2_ WHERE ... ;

INSERT INTO _table1_ (_field1_, _field2_, _field3_) VALUES ('some text', 'some text', 'some text');,如果您想添加一些值