Question

我在杀死使用以下方式创建的tkinter窗口时遇到了很多麻烦。我收到下面显示的错误。我是Python的新手，所以对您的帮助将不胜感激。

class InspectWindow(tk.Frame):
    def __init__(self, sender_email, recipient_email, email_body, 
                   master = None):
        super().__init__(master)
        self.create_widgets()

def create_widgets(self):
    self.yes = tk.Button(self)
    self.yes['text'] = 'send me!'
    self.yes['command'] = self.send_email()

def send_email(self):
    root.destroy()


root = tk.Tk()
popup = InspectWindow(sender_email, recipient_email, email_body,
                        master=root)
popup.mainloop()



Traceback (most recent call last):
  File "spam.py", line 108, in <module>
    master=root)
  File "spam.py", line 16, in __init__
    self.create_widgets()
  File "AutomateFellowshipEmails.py", line 23, in create_widgets
    self.yes['command'] = self.send_email()
  File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/tkinter/__init__.py", line 1486, in __setitem__
    self.configure({key: value})
  File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/tkinter/__init__.py", line 1479, in configure
    return self._configure('configure', cnf, kw)
  File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/tkinter/__init__.py", line 1470, in _configure
    self.tk.call(_flatten((self._w, cmd)) + self._options(cnf))
_tkinter.TclError: invalid command name ".!inspectwindow.!button"

Answer 1

您必须保留master的引用才能在其上调用方法。
（还有其他一些错误）

类似的东西（我删除了未定义的变量mail，等等...）

import tkinter as tk

class InspectWindow(tk.Frame):          # if this is a popup, you may like to inherit from tk.TopLevel?

    def __init__(self, master = None):  # removed undefined variables, you can put them back in
        self.master = master            # keep a reference of master
        super().__init__(self.master)
        self.create_widgets()
        self.pack()                     # pack into parent window

    def create_widgets(self):
        self.yes = tk.Button(self)
        self.yes['text'] = 'send me!'
        self.yes['command'] = self.send_email   # removed () call, this takes a method, not a method call
        self.yes.pack()                 # pack into self

    def send_email(self):
        self.master.destroy()           # call destroy on self.master
                                        # maybe you want to call on self instead, depending what you want to destroy


root = tk.Tk()
popup = InspectWindow(master=root)      # removed undefined variables, you can put them back in
popup.mainloop()

Answer 2

问题是这行代码：

www.site.com/folder/conn.php

与您执行此操作完全相同：

self.yes['command'] = self.send_email()

由于result = self.send_email() self.yes['command'] = reuslt破坏了根窗口，然后返回self.send_email()，因此与之相同：

None

一旦销毁了根窗口小部件（这会导致所有其他窗口小部件都被破坏），则每次尝试在窗口小部件上调用方法时都会收到错误消息。当您尝试配置root.destroy() self.yes['command'] = None时，self.yes不再存在，因此会出现错误。

解决方案是将 reference 传递给按钮的功能，这样您就不必立即调用它。您是这样做的：

self.yes

请注意，self.yes['command'] = self.send_email上没有括号。而不是立即调用该函数，而是告诉tk“这是我希望您在用户单击按钮时调用的函数的名称”。

无法销毁继承的tkinter.Tk（）窗口

2 个答案: