我试图制作一个txt文件,然后将扩展名重命名为.json,我完成了编码步骤和WriteAllLines步骤,但是如何对文本进行编码?(我有书写所需的字符串)>
这是代码
string[] lines = { "{", "\"version\": 1,", "\"schema_version\": 2,", "",
$"\"id\": \"{textBox14.Text}\",", "", $"\"title\": \"{textBox7.Text}\",",
$"\"title_localized\": \"{textBox18.Text}\",", "", $"\"artist\": \"{textBox6.Text}\",",
$"\"artist_localized\": \"{textBox8.Text}\",", $"\"artist_source\": \"{textBox9.Text}\",",
$"", $"\"illustrator\": \"{textBox10.Text}\",", $"\"illustrator_source\": \"{textBox11.Text}\",",
$"", $"\"charter\": \"{textBox13.Text}\",", $"", "\"music\": {",
$"\"path\": \"{textBox4.Text}\"", "}", "\"music_preview\": {", $"\"path\": \"{textBox5.Text}\"", "}",
"\"background\": {", $"\"path\": \"{open3.FileName}\"", "}",
"\"charts\": [", "{", "\"type\": \"easy\",", $"\"name\": \"{textBox15.Text}\",",
$"\"difficulty\": {numericUpDown1.Value},", $"\"path\": \"textBox1.Text\"", "},",
"{", "\"type\": \"hard\",", $"\"name\": \"{textBox16.Text}\",", $"\"difficulty\": {numericUpDown2.Value},",
$"\"path\": \"{textBox2.Text}\"", "},", $"]", $"", "}" };
Encoding utf8WithoutBom = new UTF8Encoding(true);
File.WriteAllLines($@"C:\Users\Public\Desktop\level files\{textBox14.Text}\level.json", lines);
应该是这样的: https://cytoid.io/level.json
答案 0 :(得分:1)
简短答案:
更改此:
File.WriteAllLines($@"C:\Users\Public\Desktop\level files\{textBox14.Text}\level.json", lines);
对此:
File.WriteAllLines($@"C:\Users\Public\Desktop\level files\{textBox14.Text}\level.json", lines, utf8WithoutBom);
长答案:
您不应该这样生成JSON;您应该使用专用的序列化器。使用当前的解决方案,如果用户输入了无效字符,则您的JSON将立即变为无效。因此,作为解决方案,您可以使用Newtonsoft的JSON.Net。这是一个示例:
类定义
public class Item
{
public int Version { get; set; }
public int SchemaVersion { get; set; }
public string Id { get; set; }
public string Title { get; set; }
public string TitleLocalized { get; set; }
public string Artist { get; set; }
public string ArtistLocalized { get; set; }
public string ArtistSource { get; set; }
public string Illustrator { get; set; }
public string IllustratorSource { get; set; }
public string Charter { get; set; }
public ItemMusic Music { get; set; }
public ItemMusicPreview MusicPreview { get; set; }
public ItemBackground Background { get; set; }
public List<ItemChart> Charts { get; set; }
}
public class ItemMusic
{
public string Path { get; set; }
}
public class ItemMusicPreview
{
public string Path { get; set; }
}
public class ItemBackground
{
public string Path { get; set; }
}
public class ItemChart
{
public string Type { get; set; }
public string Name { get; set; }
public int Difficulty { get; set; }
public string Path { get; set; }
}
对象初始化和序列化
var item = new Item
{
Version = 1,
SchemaVersion = 2,
Id = textBox14.Text,
Title = textBox7.Text,
TitleLocalized = textBox18.Text,
Artist = textBox6.Text,
ArtistLocalized = textBox8.Text,
ArtistSource = textBox9.Text,
Illustrator = textBox10.Text,
IllustratorSource = textBox11.Text,
Charter = textBox13.Text,
Music = new ItemMusic
{
Path = textBox4.Text
},
MusicPreview = new ItemMusicPreview
{
Path = textBox5.Text
},
Background = new ItemBackground
{
Path = open3.FileName
},
Charts = new List<ItemChart>
{
new ItemChart
{
Type = "easy",
Name = textBox15.Text,
Difficulty = numericUpDown1.Value,
Path = textBox1.Text
},
new ItemChart
{
Type = "hard",
Name = textBox16.Text,
Difficulty = numericUpDown2.Value,
Path = textBox2.Text
}
}
};
var settings = new JsonSerializerSettings()
{
ContractResolver = new DefaultContractResolver
{
NamingStrategy = new SnakeCaseNamingStrategy()
}
};
var json = JsonConvert.SerializeObject(item, settings);
File.WriteAllText($@"C:\Users\Public\Desktop\level files\{textBox14.Text}\level.json", json, new UTF8Encoding(true));
您当然也可以使用匿名类型代替创建完整的类定义:
var item = new {
Version = 1,
SchemaVersion = 2,
Charts = new List<object>
{
new {
Type = "easy"
}
}
}
然后将其序列化。