Question

如何使用Python2检查字符串值中是否包含确切的字符？具体来说，我希望检测它是否有美元符号（“$”），逗号（“，”）和数字。

Answer 1

假设您的字符串为s：

'$' in s        # found
'$' not in s    # not found

# original answer given, but less Pythonic than the above...
s.find('$')==-1 # not found
s.find('$')!=-1 # found

等其他角色。

......或

pattern = re.compile(r'\d\$,')
if pattern.findall(s):
    print('Found')
else
    print('Not found')

......或

chars = set('0123456789$,')
if any((c in chars) for c in s):
    print('Found')
else:
    print('Not Found')

[编辑：添加了'$' in s个答案]

Answer 2

用户Jochen Ritzel在评论用户dappawit回答这个问题时说。它应该工作：

('1' in var) and ('2' in var) and ('3' in var) ...

'1'，'2'等应替换为您要查找的字符。

有关字符串的一些信息，请参阅this page in the Python 2.7 documentation，包括使用in运算符进行子字符串测试。

更新：这与我上面的建议做的工作相同，重复次数更少：

# When looking for single characters, this checks for any of the characters...
# ...since strings are collections of characters
any(i in '<string>' for i in '123')
# any(i in 'a' for i in '123') -> False
# any(i in 'b3' for i in '123') -> True

# And when looking for subsrings
any(i in '<string>' for i in ('11','22','33'))
# any(i in 'hello' for i in ('18','36','613')) -> False
# any(i in '613 mitzvahs' for i in ('18','36','613')) ->True

Answer 3

快速比较Abbafei发布的时间：

import timeit

def func1():
    phrase = 'Lucky Dog'
    return any(i in 'LD' for i in phrase)

def func2():
    phrase = 'Lucky Dog'
    if ('L' in phrase) or ('D' in phrase):
        return True
    else:
        return False

if __name__ == '__main__': 
    func1_time = timeit.timeit(func1, number=100000)
    func2_time = timeit.timeit(func2, number=100000)
    print('Func1 Time: {0}\nFunc2 Time: {1}'.format(func1_time, func2_time))

输出：

Func1 Time: 0.0737484362111
Func2 Time: 0.0125144964371

所以代码对任何代码都更紧凑，但条件更快。

Answer 4

这将测试字符串是否由某些组合或数字，美元符号和逗号组成。这就是你要找的东西吗？

import re

s1 = 'Testing string'
s2 = '1234,12345$'

regex = re.compile('[0-9,$]+$')

if ( regex.match(s1) ):
   print "s1 matched"
else:
   print "s1 didn't match"

if ( regex.match(s2) ):
   print "s2 matched"
else:
   print "s2 didn't match"

Answer 5

我的简单，简单，简单的方法！ =D

代码

string_to_test = "The criminals stole $1,000,000 in jewels."
chars_to_check = ["$", ",", "0", "1", "2", "3", "4", "5", "6", "7", "8", "9"]
for char in chars_to_check:
    if char in string_to_test:
        print("Char \"" + char + "\" detected!")

输出

Char "$" detected!
Char "," detected!
Char "0" detected!
Char "1" detected!

谢谢！

Answer 6

检查字符是否在字符串中：

parse_string = lambda chars, string: [char in string for char in chars]

示例：

parse_string('axl', 'hello')

或

parse_string(['a', 'x', 'l'], 'hello')

<块引用>

输出：[False, False, True]

Answer 7

s=input("Enter any character:")   
if s.isalnum():   
   print("Alpha Numeric Character")   
   if s.isalpha():   
       print("Alphabet character")   
       if s.islower():   
         print("Lower case alphabet character")   
       else:   
         print("Upper case alphabet character")   
   else:   
     print("it is a digit")   
elif s.isspace():   
    print("It is space character")

其他：
打印（“非太空特殊字符”）

如何检查字符串中的特定字符？

7 个答案: