如何以JSON

Question

假设我有一个表FamousPeople和一个列Name，并带有3个名称：

1. John
2. Mary
3. Freddie Mercury

这样做：

SELECT
    'Some Random Value' AS someColumnName,
    (SELECT name FROM FamousPeople
     FOR JSON PATH) AS famousPeopleName
FOR JSON PATH, WITHOUT_ARRAY_WRAPPER

我得到这个结果：

{
  "someColumnName": "Some Random Value",
  "famousPeopleName":
  [
    {"name":"John"},
    {"name":"Mary"},
    {"name":"Freddie Mercury"}
  ]
}

我想知道是否有任何方法可以将famousPeopleName结果列作为字符串数组获取：

{
  "someColumnName": "Some Random Value",
  "famousPeopleName":
  [
    "John",
    "Mary",
    "Freddie Mercury"
  ]
}

当然，仅使用T-SQL功能，就不会在T-SQL中使用疯狂的科学家字符串操作（在荷兰也称为kick）

Answer 1

您可以使用JSON_QUERY和FOR XML构建数组，然后提取整个json片段：

declare @FamousPeople table([name] varchar(50))

insert into @FamousPeople values
('John'),('Mary'),('Freddie Mercury')

SELECT 'Some Random Value' AS someColumnName,
JSON_QUERY(
    '[' + STUFF(( SELECT ',' + '"' + [name] + '"' 
    FROM @FamousPeople 
    FOR XML PATH('')),1,1,'') + ']' ) famousPeopleName  
FOR JSON PATH, WITHOUT_ARRAY_WRAPPER 

结果：

{
    "someColumnName": "Some Random Value",
    "famousPeopleName": 
    [
        "John",
        "Mary",
        "Freddie Mercury"
    ]
}