Question

我有以下数据，想通过为“开始日期”增加29天来为每个ID创建序号。

即对于ID 1，请查找将等于1的最小值（开始日期）然后添加29。这将是Seq Num 2，然后继续直到我们遍历每个Auth ID。每次寻找每个ID的最大值（结束日期）。当此循环达到该值时，请为每个值停止它。

ID  StartDate   EndDate
1   2017-01-01  2017-01-15
1   2017-01-15  2017-02-14
2   2017-01-01  2017-01-15
2   2017-01-05  2017-03-05
2   2017-01-10  2017-02-04
3   2017-01-01  2017-01-15
3   2017-01-16  2017-01-16
3   2017-01-17  2017-01-21
3   2017-01-22  2017-02-13
3   2017-02-14  2017-03-21
3   2017-02-16  2017-03-21
4   2017-01-01  2017-01-15
4   2017-01-16  2017-02-16
4   2017-01-19  2017-02-16
4   2017-02-17  2017-03-17
4   2017-03-18  2017-03-30
4   2017-03-22  2017-03-30
4   2017-03-31  2017-04-28

Expected OutPut 
ID  SeqNum     StartDate     EndDate      New Date
1     1        2017-01-01   2017-01-15    2017-01-30
1     2        2017-01-15   2017-02-14    2017-02-28 (2017-02-28 is > than max(end date) for this ID so pick the next ID)
2     1        2017-01-01   2017-01-15    2017-01-30
2     2        2017-01-05   2017-03-05    2017-02-28
2     3        2017-01-10   2017-02-04    2017-03-29 (2017-03-29 is > than max(end date-2017-03-05) for this ID so pick the next ID)

基本上，我需要遍历每个ID，为服务日期添加29天，直到达到最大结束日期，然后输入seq num。对所有ID重复此操作。

我尝试进行CTE添加29天，但未能将其与ID的结束日期进行比较。

有人可以帮我吗？

Answer 1

你是这个意思吗？

with myData as
(
select ID,
row_Number() over (partition by Id order by id, StartDate) as SeqNum,
min(startdate) over (partition by Id) as minDate,
startDate, endDate
from myTable
)
select id, seqNum, startDate, endDate, dateadd(day, seqNum*29, minDate) as newDate
from myData;

或者这个：

with myData as
(
select ID,
row_Number() over (partition by Id order by id, StartDate) as SeqNum,
min(startdate) over (partition by Id) as minDate, 
max(endDate) over (partition by Id)as maxDate,
startDate, endDate
from myTable
)
select id, seqNum, startDate, endDate, 
 case 
 when maxDate < dateadd(day, seqNum*29, minDate)
 then maxDate 
 else dateadd(day, seqNum*29, minDate) end as newDate
from myData;

遍历每个值到seq num

1 个答案: