Question

我正在为我的网站创建一个register.php页面。这是我当前的页面代码：

$page_title = 'Register';
include('nav.html');

if($_SERVER['REQUEST_METHOD'] == 'POST'){

    require('../connect_db.php');
    $errors = array();

    if(empty($_POST['first_name'])){
        $errors[] = 'Enter your first name';
    } else {
        $fn = mysqli_real_escape_string($dbc, trim($_POST['first_name']));
    }

    if(empty($_POST['last_name'])){
        $errors[] = 'Enter your last name';
    } else {
        $ln = mysqli_real_escape_string($dbc, trim($_POST['last_name']));
    }

    if(empty($_POST['email'])){
        $errors[] = 'Enter your email';
    } else {
        $e = mysqli_real_escape_string($dbc, trim($_POST['email']));
    }

    if(!empty($_POST['pass1'])){
        if($_POST['pass1'] != $_POST['pass2']){
            $errors[] = 'Passwords do not match';
        } else {
            $p = mysqli_real_escape_string($dbc, trim($_POST['pass1']));
        }
    } else {
        $errors[] = 'Enter your password';
    }

    if(empty($errors)) {
        $q = "SELECT user_id FROM users WHERE email='$e'";
        $r = mysqli_query($dbc, $q);
        if(mysqli_num_rows($r) != 0){
            $errors[] = 'Email address already registered. <a href="login.php">Login</a>';
        }
    }

    if(empty($errors)){
        $q = "INSERT INTO users (first_name, last_name, email, pass, reg_date) VALUES ('$fn', '$ln', '$e', SHA1('$p'), NOW())";
        $r = mysqli_query($dbc, $q);

        if($r){
            echo '<h1>Registered</h1>
            <p>You are now registered!</p>
            <p><a href="login.php">Login</a></p>';
        }

        mysqli_close($dbc);
        exit();
    }
} else {
    echo '<h1>Error!</h1>
    <p id="err_msg">The following error(s) occurred:<br>';
    foreach($errors as $msg) {
        echo " - $msg<br>";
    }
    echo 'Please try again</p>';
    mysqli_close($dbc);
}
?>


<h1>Register</h1>
<form action="register.php" method="post">
<p>
    First Name: <input type="text" name="first_name" value="<?php 
if(isset($_POST['first_name'])) echo $_POST['first_name'];?>">
</p>
<p>
    Last Name: <input type="text" name="last_name" value="<?php if(isset($_POST['last_name'])) echo $_POST['last_name'];?>">
</p>
<p>
    Email: <input type="text" name="email" value="<?php if(isset($_POST['email'])) echo $_POST['email'];?>">
</p>
<p>
    Password: <input type="password" name="pass1" value="<?php if(isset($_POST['pass1'])) echo $_POST['pass1'];?>">
</p>
<p>
    Confirm Password: <input type="password" name="pass2" value="<?php if(isset($_POST['pass2'])) echo $_POST['pass2'];?>">
</p>
<p>
    <input type="submit" value="Register">
</p>
</form>`

这是我遇到的错误：

发生以下错误：

注意：未定义的变量：C：\ Abyss Web中的错误   第62行的Server \ htdocs \ register.php

警告：为C：\ Abyss Web中的foreach（）提供了无效的参数   第62行的Server \ htdocs \ register.php，请重试

Array（[type] => 2 [message] =>为提供了无效的参数   foreach（）[file] => C：\ Abyss Web Server \ htdocs \ register.php [line] =>   62）注意：未定义的变量：C：\ Abyss Web中的dbc   第67行的Server \ htdocs \ register.php

警告：mysqli_close（）期望参数1为mysqli，给定null   在第67行的C：\ Abyss Web Server \ htdocs \ register.php中

我不明白为什么会出现这些错误。我尝试在最后的else语句中定义变量，但是它仍然不执行第一个if语句。我在做什么错了？

PHP注册页面不起作用

0 个答案: