Question

遇到此错误时，我试图在python脚本中使用C函数：

Undefined symbols for architecture x86_64:
  "_PyList_Append", referenced from:
      _count_arr in mi1-5e9b85.o
  "_PyList_New", referenced from:
      _count_arr in mi1-5e9b85.o
  "_Py_BuildValue", referenced from:
      _count_arr in mi1-5e9b85.o
ld: symbol(s) not found for architecture x86_64
clang: error: linker command failed with exit code 1 (use -v to see invocation)

.cpp文件是：

#include <cstring>
#include <iostream>
//#include <Python.h>
#include "/usr/local/Cellar/python3/3.6.3/Frameworks/Python.framework/Versions/3.6/include/python3.6m/Python.h"
#include <vector>

#ifdef __cplusplus
extern "C" PyObject* count_arr(char** arr, unsigned n2, char* word)
#else
PyObject* count_arr(char** arr, unsigned n2, char* word)
#endif
{
    PyObject * PList = PyList_New(0);
    vector <int> intVector;
    for(unsigned j = 0; j < n2; j++)
    {
        if(strstr(arr[j], word) != NULL) {intVector.push_back(j);}
    }
    vector<int>::const_iterator it;
    for(it = intVector.begin(); it != intVector.end() ; it++ )
    {
        PyList_Append(PList, Py_BuildValue("i", *it));
    }
    return PList;
}

如果尝试包含Python.h，则会收到有关缺少此标头的消息。操作系统是macos。

Answer 1

我找到了答案：如果您使用clang，则需要传递

clang mi.o -I/usr/local/Cellar/python3/3.6.1/Frameworks/Python.framework/Versions/3.6/include -lpython3.6 -L /usr/local/Cellar/python3/3.6.1/Frameworks/Python.framework/Versions/3.6/lib

但是，如果您使用g ++，则需要使用命令

g++ -fPIC -c mi1.cpp -o mi.o -I/usr/local/Cellar/python3/3.6.3/Frameworks/Python.framework/Versions/3.6/include/python3.6m/
g++ -shared -lpython3.6 -L /usr/local/Cellar/python3/3.6.1/Frameworks/Python.framework/Versions/3.6/lib -olibmi.so mi.o

PyList_New的链接器错误

1 个答案: