Question

我想从一个SQL查询中打印出“多个表”。逻辑是每次打印一行具有不同于上一行值的新值，以创建HTML新表。

也许是这样

This stuff is Assigned to JOE
-----------------------------------
Assigned to |Column1   |Column2  
-----------------------------------
Joe         |1         |A
Joe         |2         |B
Joe         |3         |C


This stuff is Assigned to Adam
-----------------------------------
Assigned to |Column1   |Column2  
-----------------------------------
Adam        |1         |A
Adam        |2         |B


This stuff is Assigned to Patrick
-----------------------------------
Assigned to |Column1   |Column2  
-----------------------------------
Patrick     |1         |A
Patrick     |2         |B
Patrick     |3         |C

我对我的代码进行了测试运行，这是一个基本的PHP If-Statement，它试图检测上一行的变量是否未更改。如果可以，则插入一些代码。

$tsql = "
SELECT 
    id
    AssignedTo
    Column1
    Column2
FROM somewhere
ORDER BY AssignedTo ASC";  

/* Execute the query. */  
$stmt = sqlsrv_query( $conn, $tsql);  

/* I will set this variable to whatever for now */ 
$AssignedTo = '';

while( $row = sqlsrv_fetch_array( $stmt, SQLSRV_FETCH_NUMERIC))  
{       

If ($AssignedTo != $row[1])
    {
    $AssignedTo = $row[1];
    echo "<h1>This is assigned to ".$AssignedTo."</h1>";
    echo "<table><tr>headings</tr>";
    }

echo "<tr>bla bla</tr>";

}

但是结果却是这样的：

This stuff is Assigned to JOE
--------------------------------
This stuff is Assigned to Adam
--------------------------------
This stuff is Assigned to Patrick
--------------------------------
//Rest of the Rows down here after

即使 if语句在内之内，我也不明白为什么我的“东西分配给”为什么在所有其余表行上循环显示>。

谢谢

Answer 1

启动表格后，您再也没有关闭过表格。

while( $row = sqlsrv_fetch_array( $stmt, SQLSRV_FETCH_NUMERIC))
{

If ($AssignedTo != $row[1])
    {
    if ($AssignedTo != '') {
        echo '</table>';
    }
    $AssignedTo = $row[1];
    echo "<h1>This is assigned to ".$AssignedTo."</h1>";
    echo "<table><tr>headings</tr>";
    }

echo "<tr>bla bla</tr>";

}

每次行值更改时插入其他HTML

1 个答案: