Question

我找到了这段代码，用于填写范围表here。

DATA   lr_vkorg   TYPE RANGE OF vkorg.
TYPES: lr_range_t TYPE RANGE OF vkorg.

lr_vkorg = VALUE lr_range_t(
          LET s = 'I'
              o = 'EQ'
          IN sign   = s
             option = o
             ( low = '1100' )
             ( low = '1200' )
             ( low = '1300' )
             ( low = '1400' )
             ( low = '1500' )
).

但是不要做这样的事情：

( low = '1' )
( low = '2' )
...

我想用内部表['1', '2', ...]的值填充它。
有谁知道如何做到这一点？

这是我根据答案进行的操作：

DATA:
  lt_itab       TYPE TABLE OF string,
  lt_range_itab TYPE RANGE OF string
  .

APPEND '1'  TO lt_itab.
APPEND '2'  TO lt_itab.
APPEND '3'  TO lt_itab.
APPEND '4'  TO lt_itab.

lt_range_itab = VALUE #(
  FOR <ls_itab> IN lt_itab
  ( sign = 'I'
    option = 'EQ'
    low = <ls_itab> )
).

Answer 1

lr_vkorg = VALUE # ( sign   = 'I'  option = 'EQ' ( low = '1100' ) ( low = '1200' )
             ( low = '1300' ) ( low = '1400' )   ( low = '1500' ) ).

Answer 2

您可以像这样使用声明的结构声明宏：

each(function ($article) {
    $article->category_id = KnowledgeBaseCategory::find($article->category_id)->name;
});

然后使用此单线填充范围：

DEFINE range.
 lr_vkorg = VALUE lr_range_t( BASE lr_vkorg ( sign = 'I' option = 'EQ' low = &1 ) ).
END-OF-DEFINITION.

如果我们要谈论itab的填充范围，请使用以下语句：

range: '1100', '1200', '1300', '1400', '1500', '1600'.

使用LET从Itab填充范围表

2 个答案: