Question

我正在尝试解决的一个有趣问题：

我需要限制要带队的员工人数（下面代码中的数字）

employee.txt 示例部分：

30;电气工程师; 1; 70

31;科学家; 0; 100

32; doctor; 0; 42

33;科学家; 1; 47

34;机械的； 0; 63

我按性别和专业列出了每个人的总数。有我的代码：

manager = 1
cook = 3
electrical_engineer = 4
computers_specialist = 5
doctor = 5
mechanic = 8
scientist = 14

expedition_total = 40
female_min = 21
male_min = 12

def total_resist_count():

    with open('employee.txt', 'r') as employee_list:

        total_count = 0
        female_count = 0
        male_count = 0
        expedition = []

        for employee in employee_list.readlines():
            employee_data = employee.rstrip().split(';')
            if int(employee_data[3]) >= 60:
                total_count += 1

            if int(employee_data[2] == '0') and int(employee_data[3]) >= 60:
                female_count += 1

            if int(employee_data[2] == '1') and int(employee_data[3]) >= 60:
                male_count += 1

        print('Stress-resistant colonists: ', total_count)
        print('--------- Female colonists: ', female_count)
        print('----------- Male colonists: ', male_count)
        print('--------------------------')
        print('Mars expedition list: ')
        pprint(expedition)


if __name__ == '__main__':
    total_resist_count()

输出：

耐压力的殖民者：90

---------女殖民者：48

-----------男性殖民者：42


火星探险名单：

[]

我需要将每个专家计数添加到探险中（仅限于代码中的var-总共40个）

我尝试：

 if int(employee_data[2] == '0') and int(employee_data[3]) >= 60:
        expedition.append(employee_data)
        female_count += 1

并且：

if int(employee_data[2] == '0') and int(employee_data[3]) >= 60:
            female_count += 1
            for female_employee in range(total_count - male_min):
                expedition.append(female_employee)

1）但是我得到了拥有 employee_data [2] =='0'和
的员工的完整列表 employee_data [3]）> = 60 （显然）

2）我得到一个重复的数字

如何限制新列表添加到需要的数字后？

赞赏所有建议并指出错误

Answer 1

尝试：

manager = 1
cook = 3
electrical_engineer = 4
computers_specialist = 5
doctor = 5
mechanic = 8
scientist = 14

expedition_total = 40
female_min = 21
male_min = 12

    def total_resist_count():

        with open('employee.txt', 'r') as employee_list:

            total_count = 0
            female_count = 0
            male_count = 0
            expedition = []

            for employee in employee_list.readlines():
                employee_data = employee.rstrip().split(';')
                if int(employee_data[2] == 0) and int(employee_data[3]) >= 60:
                    female_count += 1
                    total_count += 1
                    expedition.append(employee_data)

                elif int(employee_data[2] == 1) and int(employee_data[3]) >= 60:
                    male_count += 1
                    total_count += 1
                    expedition.append(employee_data)

        print('Stress-resistant colonists: ', total_count)
        print('--------- Female colonists: ', female_count)
        print('----------- Male colonists: ', male_count)
        print('--------------------------')
        print('Mars expedition list: ')
        print(expedition)


    if __name__ == '__main__':
        total_resist_count()

如果需要更具体的参数，请在条件语句中添加它们。就像如果您需要某种类型的员工的最小/最大数量一样，只需检查此类员工的流动总数是否在界限之内，并且是否在允许范围内，则相应地追加或忽略。

如果最多可容纳40人，请使用：

manager = 1
cook = 3
electrical_engineer = 4
computers_specialist = 5
doctor = 5
mechanic = 8
scientist = 14

expedition_total = 40
female_min = 21
male_min = 12

total_count = 0
female_count = 0
male_count = 0
expedition = []

    def total_resist_count():
        global total_count
        global female_count
        global male_count
        global expedition

        with open('employee.txt', 'r') as employee_list:
            while len(expedition) < total_count:

                for employee in employee_list.readlines():
                    employee_data = employee.rstrip().split(';')
                    if int(employee_data[2] == '0') and int(employee_data[3]) >= 60:
                        female_count += 1
                        total_count += 1
                        expedition.append(employee_data)

                    elif int(employee_data[2] == '1') and int(employee_data[3]) >= 60:
                        male_count += 1
                        total_count += 1
                        expedition.append(employee_data)

        print('Stress-resistant colonists: ', total_count)
        print('--------- Female colonists: ', female_count)
        print('----------- Male colonists: ', male_count)
        print('--------------------------')
        print('Mars expedition list: ')
        print(expedition)


    if __name__ == '__main__':
        total_resist_count()

如何限制列表中的追加元素数量

1 个答案: