Question

我需要从向量中删除\"。这是我的数据：

data <- c("\"https://click.linksynergy.com/link?id=RUxZriH*PWc&offerid=323058.1803224&type=2&murl=https%3A%2F%2Fwww.udemy.com%2Flinux-linux-security-masterclass-3-in-1%2F", 
"\"https://click.linksynergy.com/link?id=RUxZriH*PWc&offerid=323058.1848638&type=2&murl=https%3A%2F%2Fwww.udemy.com%2Fmastering-kali-linux%2F", 
"\"https://click.linksynergy.com/link?id=RUxZriH*PWc&offerid=323058.1426684&type=2&murl=https%3A%2F%2Fwww.udemy.com%2Finformation-gathering-with-kali-linux%2F", 
"\"https://click.linksynergy.com/link?id=RUxZriH*PWc&offerid=323058.1628300&type=2&murl=https%3A%2F%2Fwww.udemy.com%2Flinux-switchblade%2F", 
"\"https://click.linksynergy.com/link?id=RUxZriH*PWc&offerid=323058.1615700&type=2&murl=https%3A%2F%2Fwww.udemy.com%2Fadministrador-de-sistemas-junior-en-windows-server-y-linux%2F", 
"\"https://click.linksynergy.com/link?id=RUxZriH*PWc&offerid=323058.809770&type=2&murl=https%3A%2F%2Fwww.udemy.com%2Flearn-bash-shell-in-linux-for-beginners-lite%2F", 
"\"https://click.linksynergy.com/link?id=RUxZriH*PWc&offerid=323058.574388&type=2&murl=https%3A%2F%2Fwww.udemy.com%2Fhow-to-install-linux-ubuntu-server%2F", 
"\"https://click.linksynergy.com/link?id=RUxZriH*PWc&offerid=323058.1436610&type=2&murl=https%3A%2F%2Fwww.udemy.com%2Fcentos-and-ubuntu-managing-packages%2F", 
"\"https://click.linksynergy.com/link?id=RUxZriH*PWc&offerid=323058.1771266&type=2&murl=https%3A%2F%2Fwww.udemy.com%2Flinux-foundation-certified-system-administrator-exam%2F", 
"\"https://click.linksynergy.com/link?id=RUxZriH*PWc&offerid=323058.1734052&type=2&murl=https%3A%2F%2Fwww.udemy.com%2Flinux-server-security%2F"
)

如您所见，每个对象都以\"开头。如何专门删除这些字符并保留链接？

Answer 1

您可以尝试一下。请注意，您真正想要的是删除npm install，而不是\"（这是在问题的未编辑版本中建议的）。您需要代表字符中的每个元素的第一个"\。

Answer 2

或者我们可以仅在模式上使用'"'

gsub('"', "", data)

Answer 3

如果它始终是第一个字符，则只需使用 substring ：

substring(data, 2)

这应该比任何 regex 解决方案都要快。

data <- rep(data, 1000)

microbenchmark::microbenchmark(
  a = substring(data, 2),  
  b = gsub("\"", "", data, fixed = TRUE),
  c = gsub('"', "", data),
  d = gsub('[\"]', '', data),
  e = stringr::str_replace(data, '[\"]', ''),
  f = gsub("^.","",data)
  )
# Unit: milliseconds
# expr       min        lq      mean    median        uq       max neval
#    a  2.835013  2.849838  2.933796  2.857393  2.900301  4.446956   100
#    b  4.728632  4.739751  4.788882  4.754861  4.795203  5.200185   100
#    c  7.388025  7.413684  7.503427  7.458444  7.555520  8.160925   100
#    d  7.390876  7.412686  7.530044  7.454453  7.533568  8.535544   100
#    e 12.019154 12.205608 12.430870 12.316084 12.581081 13.917336   100
#    f 15.712882 15.735975 15.875353 15.770043 15.861275 18.906262   100

Answer 4

使用fixed = TRUE将模式作为字符串进行匹配：

gsub("\"", "", data, fixed = TRUE)

Answer 5

@milan更快：）

使用 stringr 的方法是

library(stringr)
str_replace(data, '[\"]', '')

Answer 6

这同样有效：

gsub("\"", "", data)

Answer 7

您也可以删除第一个字符，跳过反斜杠头痛：

gsub("^.","",data)

Answer 8

我结合使用gsub（）和noquote（）

for (i in data){
   print(gsub('"','',(noquote(i))))
}

从字符串中删除双引号\“符号

8 个答案: