Question

我有两个数组，如：

$team = [
    ['id' => 1, 'name' => 'Team A'],
    ['id' => 2, 'name' => 'Team B'],
    ['id' => 3, 'name' => 'Team C'], 
]; 

$people = [
    ['id' => 1, 'name' => 'Mark Hamill', 'team' => 1],
    ['id' => 2, 'name' => 'Nicolas Cage', 'team' => 2],
    ['id' => 3, 'name' => 'Tom Cruise', 'team' => 3],
    ['id' => 4, 'name' => 'Tom Hanks', 'team' => 1],
    ['id' => 5, 'name' => 'Brad Pitt', 'team' => 2],
    ['id' => 6, 'name' => 'Paul Smith', 'team' => 3],
    ['id' => 7, 'name' => 'Matt Daemon', 'team' => 1],
    ['id' => 8, 'name' => 'Robert Redford', 'team' => 2],
]

我想根据团队ID将$ people数组合并为$ team数组作为子节点。因此结果将是：

$team = [
    [
        'id' => 1, 
        'name' =>'Team A',
        'members' => [
            ['id' => 1, 'name' => 'Mark Hamill', 'team' => 1],
            ['id' => 4, 'name' => 'Tom Hanks', 'team' => 1],
            ['id' => 7, 'name' => 'Matt Daemon', 'team' => 1],
        ]
    ],
    [
        'id' => 2, 
        'name' =>'Team B',
        'members' => [
            ['id' => 2, 'name' => 'Nicolas Cage', 'team' => 2],
            ['id' => 5, 'name' => 'Brad Pitt', 'team' => 2],
            ['id' => 8, 'name' => 'Robert Redford', 'team' => 2],
        ]
    ],
    [
        'id' => 3, 
        'name' =>'Team C',
        'members' => [
            ['id' => 3, 'name' => 'Tom Cruise', 'team' => 3],
            ['id' => 6, 'name' => 'Paul Smith', 'team' => 3],
        ]
    ], 
];

我知道我可以遍历$ team并根据他们的“ team” ID一次添加一个相关的$ people，但是我想知道是否有更有效的方法。在我的项目中，这两个数组中的每个数组都可以增长到最多包含约50个项目，并且一次处理这些数组确实使页面速度变慢。

谢谢

Answer 1

这将循环$ teams数组并与array_column相交以获得所需的数组。

$teampeople = array_column($people, "team");
//Creates a lookup array of the teams from people array

foreach($team as &$t){
    // Here I match from the lookup array and get the "main" arrays.  
    // Array_values remove the indexed from the resulting array to make it 0,1,2 etc.
    $t['members'] = array_values(array_intersect_key($people, array_intersect($teampeople, [$t['id']])));
}
unset($t); // just to make sure you don't accidentally change the array
var_dump($team);

输出：

array(3) {
  [0]=>
  array(3) {
    ["id"]=>
    int(1)
    ["name"]=>
    string(6) "Team A"
    ["members"]=>
    array(3) {
      [0]=>
      array(3) {
        ["id"]=>
        int(1)
        ["name"]=>
        string(11) "Mark Hamill"
        ["team"]=>
        int(1)
      }
      [1]=>
      array(3) {
        ["id"]=>
        int(4)
        ["name"]=>
        string(9) "Tom Hanks"
        ["team"]=>
        int(1)
      }
      [2]=>
      array(3) {
        ["id"]=>
        int(7)
        ["name"]=>
        string(11) "Matt Daemon"
        ["team"]=>
        int(1)
      }
    }
  }
  [1]=>
  array(3) {
    ["id"]=>
    int(2)
    ["name"]=>
    string(6) "Team B"
    ["members"]=>
    array(3) {
      [0]=>
      array(3) {
        ["id"]=>
        int(2)
        ["name"]=>
        string(12) "Nicolas Cage"
        ["team"]=>
        int(2)
      }
      [1]=>
      array(3) {
        ["id"]=>
        int(5)
        ["name"]=>
        string(9) "Brad Pitt"
        ["team"]=>
        int(2)
      }
      [2]=>
      array(3) {
        ["id"]=>
        int(8)
        ["name"]=>
        string(14) "Robert Redford"
        ["team"]=>
        int(2)
      }
    }
  }
  [2]=>
  &array(3) {
    ["id"]=>
    int(3)
    ["name"]=>
    string(6) "Team C"
    ["members"]=>
    array(2) {
      [0]=>
      array(3) {
        ["id"]=>
        int(3)
        ["name"]=>
        string(10) "Tom Cruise"
        ["team"]=>
        int(3)
      }
      [1]=>
      array(3) {
        ["id"]=>
        int(6)
        ["name"]=>
        string(10) "Paul Smith"
        ["team"]=>
        int(3)
      }
    }
  }
}

https://3v4l.org/kmvuR

Answer 2

尝试一下：

foreach ($team as $t) {
    $t['members'] = array_filter($people, function ($var) use ($t) {
    return ($var['team'] == $t['id']);
})
}

PHP：如何通过键合并两个嵌套的数组

2 个答案: