Question

这只是一个有趣的项目，我认为做起来很酷，但我一直在努力找出答案。

plates = [100, 45, 35, 25, 10, 5, 2.5]
goal_weight = 425
starting_weight = 45
while goal_weight > starting_weight:

我的想法是用while循环遍历板块。我需要每个数字以最大程度地达到目标权重（100进入450次4次），然后移至下一个数字并尝试在其中进行尝试，以显示加载杆的理想方式。但是我在这里可能走错了路。

示例：250 = 45lb bar（starting_weight），两个100lb板，两个2.5lb板 425 = 45lb bar，两个100lb，四个45lb

想要打印类似的内容：两个100，两个45，两个10

Answer 1

这里有个小程序，可以找到合适的重量盘组合。请注意功能zip，该功能zip将重量板数量列表和重量列表结合在一起。 list(zip(nweights, weights))形成一个元组列表，例如[(4, 100), (0, 45) ... (0, 2), (0, 2.5)]

weights=[100, 45, 35, 25, 10, 5, 2, 2.5]
targetweight = int(input('What is the target weight: '))

nweights = []
remaining = targetweight
for  i, weight in enumerate(weights):
    nweights.append(int(remaining/ weight))
    remaining = remaining - nweights[i]*weights[i]
    if remaining == 0:
        break

listweights=zip(nweights, weights)
for weight in listweights:
    print(f'you need {weight[0]} of weight {weight[1]} pound')

if remaining !=0:
    print(f'the correct weight combination cannot be found,'
          f'the remaining weight is: {remaining} pound')

Answer 2

这就是我最终得到的。谢谢大家的帮助！

weights=[100, 45, 35, 25, 10, 5, 2.5]
target_weight = int(input('How much weight do you need? '))
bar_weight = int(input('Enter bar weight: '))

nweights = []
remaining = target_weight - bar_weight
for  i, weight in enumerate(weights):
    if int(remaining / weight) % 2 == 0:
        nweights.append(int(remaining/ weight))
    else:
        nweights.append(int(remaining/ weight) - 1)
    remaining = remaining - nweights[i]*weights[i]
    if remaining == 0:
        break

listweights=zip(nweights, weights)
print(f'{bar_weight}lb bar')
for weight in listweights:
    if weight[0] >= 2:
        print(f"{weight[0]} | {weight[1]}'s")

if remaining !=0:
    print(f'the correct weight combination cannot be found,'
          f'the remaining weight is: {remaining} pound')

Answer 3

是的，我认为您的解决方案有效，尽管以下代码段可能更合逻辑... （使用一些numpy数组方法）

$str = 'DisplayText="cf font=&quot;Arial" size="10" complexscriptsfont="Arial&quot; complexscriptssize="10" asiantextfont=&quot;Arial" fontcolor="595959"">';
$splitted = explode('"', $str);
$splittedSize = count($splitted);
$result = $splitted[0].'"'.implode('&quot;',array_slice($splitted,1,$splittedSize-2)).$splitted[$splittedSize-1].'"';
echo $result;

Python3构建简单的健身工具

3 个答案: