Question

我是python和一般编程人员的新手，我发现循环非常混乱。我不需要经常使用循环，但是我目前正在开发一个简单的游戏（脚，Nuke，蟑螂，类似于Rock，Paper和Scissors），而且我很确定我的基本逻辑已经成功，但是我无法获得如何在各回合中进行计数的逻辑，因为我必须将其绑定到if语句（我猜）或类似的东西。我还希望能够计算出玩家赢得了多少回合以及多少次是平局。玩家正在与一台根据随机数生成其回复的计算机对战。

import random

number = random.randint(1,3)

if number == 1:
    chosen1 = "Foot"
elif number == 2:
    chosen1 = "Nuke"
else:
    chosen1 = "Cockroach"

chosen2 = input("Foot, Nuke or Cockroach? (Quit ends):")

def choice(chosen1, chosen2):
    if (chosen1 == "Nuke" and chosen2=="Nuke"):
        print("You chose: ", chosen2)
        print("Computer chose: ", chosen1)
        print("You LOSE!")
    elif chosen1 == chosen2:
        print("You chose: ", chosen2)
        print("Computer chose: ", chosen1)
        print("It is a tie!")
    elif (chosen1 == "Foot" and chosen2=="Cockroach"):
        print("You chose: ", chosen2)
        print("Computer chose: ", chosen1)
        print("You LOSE!")
    elif (chosen2 == "Foot" and chosen1=="Cockroach"):
        print("You chose: ", chosen2)
        print("Computer chose: ", chosen1)
        print("You WIN!")
    elif (chosen1 == "Nuke" and chosen2=="Foot"):
        print("You chose: ", chosen2)
        print("Computer chose: ", chosen1)
        print("You LOSE!")
    elif (chosen2 == "Nuke" and chosen1=="Foot"):
        print("You chose: ", chosen2)
        print("Computer chose: ", chosen1)
        print("You WIN!")
    elif (chosen1 == "Cockroach" and chosen2=="Nuke"):
        print("You chose: ", chosen2)
        print("Computer chose: ", chosen1)
        print("You LOSE!")
    elif (chosen2 == "Cockroach" and chosen1=="Nuke"):
        print("You chose: ", chosen2)
        print("Computer chose: ", chosen1)
        print("You WIN!")
    elif chosen2 =="Quit":
        quit()

while chosen2 != "Quit":
    choice(chosen1, chosen2)
    chosen2 = input("Foot, Nuke or Cockroach? (Quit ends):")

有人可以建议我如何处理此循环吗？编辑：我希望在用户退出后打印获胜，平局和回合的次数。

Answer 1

好吧，您可以在每个if语句中添加一个return语句。如果是平局，则返回0；如果玩家获胜，则返回1；否则，返回2。

然后只需添加

>> 9007199254740992 == 9007199254740993
ans =
    logical
       1

这就是结果。然后将其与更多if进行比较，并添加平局和获胜变量。这很丑，但应该可以。

Answer 2

您的循环似乎没问题。您只需要将结果保存在可以更新的变量中即可。您可以在名为choice的函数中为每个结果使用return语句，或者仅需一点点定义即可

wins = 0
ties = 0

在程序的开头，然后添加一个

wins += 1
# or ties += 1

程序的每个可能结果

Answer 3

您可以像这样对赢和输进行查表：

who_wins = {('Cockroach','Nuke'): True,
            ('Foot', 'Cockroach'): True,
            ('Nuke', 'Foot'): True}

这样，您可以运行类似的功能

def check_winner(player, cpu):
    result = who_wins.get((player,cpu), False)
    return result

然后检查状态

result = check_winner(chosen2, chosen1)
if result:
   print("You won!")
   your_wins+=1
else:
   print("You lost!")
   computer_wins+=1

总共看起来像

import random

your_wins, cpu_wins = 0,0

who_wins = {('Cockroach','Nuke'): True,
            ('Foot', 'Cockroach'): True,
            ('Nuke', 'Foot'): True}

def check_winner(player, cpu):
    result = who_wins.get((player,cpu), False)
    return result

while True:
    number = random.randint(1,3)

    if number == 1:
        chosen1 = "Foot"
    elif number == 2:
        chosen1 = "Nuke"
    else:
        chosen1 = "Cockroach"

    chosen2 = input("Foot, Nuke or Cockroach? (Quit ends):")

    if chosen2.lower() != "quit":
        result = check_winner(chosen2, chosen1)
        if result:
           print("You won!")
           your_wins += 1
        else:
           print("You lost!")
           cpu_wins +=1
    else:
        quit()

Answer 4

基本上：您需要声明一个计数变量，并在每次新回合开始时向该变量加1，然后可以打印该回合编号。如果您使用了数字（如您应该那样），则会得到一个错误，请使用str（）方法来解决此问题。

我已经在repl.it上实现了 https://repl.it/@conradkay/WarpedPrevailingQuerylanguage

Answer 5

import random

options = ['Foot','Nuke','Cockroach']
computer_number = random.randint(0,2)
computer_choice = options[computer_number]
def choice(chosen1, chosen2):
    print("You chose: ", chosen2)
    print("Computer chose: ", chosen1)
    if (computer_choice,player_choice) == ('Nuke','Nuke'):
        print("You LOSE!")
        return 'Loss'
    if (computer_choice==player_choice):
        print("It is a tie!")
        return 'Tie'    
    player_number = options.index(player_choice)
    result = (player_number-computer_number)%3
    if result == 2:        
        print(['You LOSE'])
        return 'Loss'
    if result == 1:
        print(['You WIN!'])
        return 'Win'

result_counts = {'Win':0,'Loss':0,'Tie':0}

while True:
    player_choice = input("Foot, Nuke or Cockroach? (Quit ends):")
    if player_choice == 'Quit':
        break
    result = choice(computer_choice, player_choice)
    results_counts[result] = results_counts[result]+1

请注意，如果您希望计算机每次都做出不同的选择，则应将行

computer_number = random.randint(0,2)
computer_choice = options[computer_number]

在while循环内

。另外请注意，您忽略了很多有效性检查。

Python：在游戏上添加计数器

5 个答案: