当尝试将简单数据框保存到mysql时,出现以下警告:
C:... \ anaconda3 \ lib \ site-packages \ pymysql \ cursors.py:170:警告:(1366,“不正确的字符串值:'\ x92 \ xE9t \ xE9)'位于'VARIABLE_VALUE'列518“) 结果= self._query(查询)
和
C:... anaconda3 \ lib \ site-packages \ pymysql \ cursors.py:170:警告: (3719,“'utf8'当前是字符集UTF8MB3的别名, 但它将在将来的版本中成为UTF8MB4的别名。请考虑 使用UTF8MB4以便明确。“)result = self._query(query)
环境信息:我使用Mysql8,python3.6(pymysql 0.9.2,sqlalchemy 1.2.1)
我访问了一个类似波纹管的帖子,似乎都没有提供有关如何避免此警告的解决方案。
N.B:mysql表中的归类似乎未设置为我在create_db
类的Connection
函数中指定的归类。
可执行代码:
import DataEngine.db.Connection as connection
import random
import pandas as pd
if __name__ == "__main__":
conn = connection.Connection(host="host_name", port="3306", user="username", password="password")
conn.create_db("raw_data")
conn.establish("raw_data")
l1 = []
for i in range(10):
l_nested = []
for j in range(10):
l_nested.append(random.randint(0, 100))
l1.append(l_nested)
df = pd.DataFrame(l1)
conn.save(df, "random_df")
df2 = conn.retrieve("random_df")
print(df2)
因此数据库中保留的数据框为:
index 0 1 2 3 4 5 6 7 8 9
0 0 11 57 75 45 81 70 91 66 93 96
1 1 51 43 3 64 2 6 93 5 49 40
2 2 35 80 76 11 23 87 19 32 13 98
3 3 82 10 69 40 34 66 42 24 82 59
4 4 49 74 39 61 14 63 94 92 82 85
5 5 50 47 90 75 48 77 17 43 5 29
6 6 70 40 78 60 29 48 52 48 39 36
7 7 21 87 41 53 95 3 31 67 50 30
8 8 72 79 73 82 20 15 51 14 38 42
9 9 68 71 11 17 48 68 17 42 83 95
我的Connection class
import sqlalchemy
import pymysql
import pandas as pd
class Connection:
def __init__(self: object, host: str, port: str, user: str, password: str):
self.host = host
self.port = port
self.user = user
self.password = password
self.conn = None
def create_db(self: object, db_name: str, charset: str = "utf8mb4", collate:str ="utf8mb4_unicode_ci",drop_if_exists: bool = True):
c = pymysql.connect(host=self.host, user=self.user, password=self.password)
if drop_if_exists:
c.cursor().execute("DROP DATABASE IF EXISTS " + db_name)
c.cursor().execute("CREATE DATABASE " + db_name + " CHARACTER SET=" + charset + " COLLATE=" + collate)
c.close()
print("Database %s created with a %s charset" % (db_name, charset))
def establish(self: object, db_name: str, charset: str = "utf8mb4"):
self.conn = sqlalchemy.create_engine(
"mysql+pymysql://" + self.user + ":" + self.password + "@" + self.host + ":" + self.port + "/" + db_name +
"?charset=" + charset)
print("Connection with database : %s has been established as %s at %s." % (db_name, self.user, self.host))
print("Charset : %s" % charset)
def retrieve(self, table):
df = pd.read_sql_table(table, self.conn)
return df
def save(self: object, df: "Pandas.DataFrame", table: str, if_exists: str = "replace", chunksize: int = 10000):
df.to_sql(name=table, con=self.conn, if_exists=if_exists, chunksize=chunksize)
答案 0 :(得分:1)
嗯,十六进制92和e9无效utf8mb4(UTF-8)。假设您是’été
,假设使用CHARACTER SETs
cp1250,cp1256,cp1257或latin1。
找出该文本来自何处,然后决定它是否有效latin1
。 然后我们可以修复代码以声明客户端确实在使用latin1,而不是utf8mb4?或者,我们可以修复客户端以使用UTF-8,从长远来看,这可能会更好。