它在phpmyadmin syntax error near 'SELECT c.candidate_id AS candidate_id,c.date_time_stamp AS candidate_date_time,c' at line 1
SELECT * FROM states ORDER BY name ASC
SELECT c.candidate_id AS candidate_id,
c.date_time_stamp AS candidate_date_time,
c.first_name AS first_name, c.last_name AS last_name,
c.availability_date AS availability_date,
c.experience_years AS experience_years,
c.phone AS phone,c.phone_alternate AS phone_alternate,
c.email AS email,c.bridge AS bridge,c.hot AS hot,
c.submitted AS submitted,c.placed AS placed,
sp.abbreviation AS specialty_abbreviation,
jt.name AS candidate_job_type,s.first_name AS staff_first_name
FROM candidates c
LEFT JOIN specialties sp ON sp.specialty_id=c.specialty_id
LEFT JOIN candidate_job_types jt ON jt.candidate_job_type_id=c.candidate_job_type_id
LEFT JOIN staff s ON s.staff_id=c.staff_id
WHERE c.active=1 AND
( CONCAT_WS(' ', c.first_name, c.last_name) LIKE '%gmail%' OR c.phone = 'gmail' OR
c.phone_alternate = 'gmail' OR c.email = 'gmail') GROUP BY c.candidate_id
ORDER BY c.date_time_stamp DESC LIMIT 0,100
答案 0 :(得分:6)
由于合并了两个SELECT
语句,您有错误。如果你用;
分隔它们,它应该有效。
SELECT *
FROM states
ORDER BY name ASC;
SELECT c.candidate_id AS candidate_id,c.date_time_stamp AS candidate_date_time,
c.first_name AS first_name, c.last_name AS last_name,
c.availability_date AS availability_date,
c.experience_years AS experience_years,c.phone AS phone,
c.phone_alternate AS phone_alternate,c.email AS email,c.bridge AS bridge,
c.hot AS hot,c.submitted AS submitted,c.placed AS placed,
sp.abbreviation AS specialty_abbreviation,jt.name AS candidate_job_type,
s.first_name AS staff_first_name
FROM candidates c
LEFT JOIN specialties sp
ON sp.specialty_id=c.specialty_id
LEFT JOIN candidate_job_types jt
ON jt.candidate_job_type_id=c.candidate_job_type_id
LEFT JOIN staff s
ON s.staff_id=c.staff_id
WHERE c.active=1
AND ( CONCAT_WS(' ', c.first_name, c.last_name) LIKE '%gmail%'
OR c.phone = 'gmail'
OR c.phone_alternate = 'gmail'
OR c.email = 'gmail'
)
GROUP BY c.candidate_id
ORDER BY c.date_time_stamp DESC
LIMIT 0,100;
答案 1 :(得分:0)
您正在一起执行两个select语句。使用分号:
SELECT * FROM states ORDER BY name ASC;
SELECT c.candidate_id AS [...]
答案 2 :(得分:0)
问题刚刚开始:SELECT * FROM states ORDER BY name ASC SELECT c.candidate_id ...
。
使用分号分隔不同的搜索:SELECT * FROM states ORDER BY name ASC; SELECT c.candidate_id...