Question

我无法弄清楚为什么会出现此错误：传递给App \ src \ Manager :: manage（）的参数1必须是App \ src \ ManageableInterface的实例，是给定的App \ src \ Worker的实例。我将代码编码为ManageableInterface接口，而不是具体的类，但是它不起作用。这是代码：

ManageableInterface.php

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SleepableInterface.php

<?php namespace App\src\interfaces;

interface ManageableInterface
{
  public function manage();
}

WorkableInterface.php

<?php namespace App\src\interfaces;

interface SleepableInterface
{
  public function sleep();
}

Worker.php

<?php namespace App\src\interfaces;

interface WorkableInterface
{
 public function work();
}

Manager.php

<?php namespace App\src;

use App\src\interfaces\{WorkableInterface, SleepableInterface, ManageableInterface};

class Worker implements WorkableInterface, SleepableInterface, ManageableInterface
{
  public function work()
  {
    var_dump('Worker is working.');
  }


  public function sleep()
  {
    var_dump('Worker is sleeping.');
  }


  public function manage()
  {
    $this->work();
    $this->sleep();
  }

}

index.php

<?php namespace App\src;

class Manager
{
  public function manage(ManageableInterface $worker)
  {
    $worker->manage();
  }
 }

通过具体类，而不是带有已实现接口php的类

0 个答案: