Question

我有表T1：

Id    Invoice    Date
1     A100
2     B100

我想用ID为基础的递增日期更新表T1

所需结果：

Id    Invoice    Date
1     A100       GetDate()
2     B100       GetDate()+1

是否有可用的东西像这样

：

update T1
set [Date]= GetDate() + ROW_NUMBER() over (order by id)
from T1

Answer 1

使用与Larnu类似但更直接的方法，您可以直接更新CTE：

WITH cte AS
(
    SELECT  *
    ,       ROW_NUMBER() over (order by id) rn
    FROM    T1
)

UPDATE cte
    SET [date] = DATEADD(DAY, rn, GETDATE())

Answer 2

这是您要寻找的东西吗？根据ID

更新日期列

    update T1
    set [Date]= GetDate() + (id-1)
    from T1

Answer 3

使用dateadd

    update T2     
    SET  T2.D=dateadd(dd,T3.rn,getdate())
      FROM 
      T1 as t2 INNER JOIN 
      (
      select *,ROW_NUMBER() over (order by [id]) as rn from T1
      ) T3 ON t2.id=t3.id

Answer 4

一种方法是使用CTE使用ROW_NUMBER和DATEADD评估新日期，然后使用CTE中的值UPDATE评估新日期：

USE Sandbox;
GO

CREATE TABLE TestTable (ID int IDENTITY, SomeDate date)
INSERT INTO dbo.TestTable (SomeDate)
VALUES (GETDATE()),(GETDATE()),(GETDATE()),(GETDATE()),(GETDATE());
GO

SELECT *
FROM TestTable;
GO
WITH NewDates AS(
    SELECT ID, DATEADD(DAY, ROW_NUMBER() OVER (ORDER BY TT.ID), GETDATE()) AS NewDate
    FROM dbo.TestTable TT)
UPDATE TT
SET SomeDate = ND.NewDate
FROM dbo.TestTable TT
     JOIN NewDates ND ON TT.ID = ND.ID;
GO
SELECT *
FROM TestTable;

GO
DROP TABLE TestTable;
GO

Answer 5

使用recursive cte生成Id和dates，然后根据join列Id来更新表中的数据

with cte as ( 
  select 1 AS Id, getdate() as dt
  union all
  select cte.Id+1, dateadd(d,1,cte.dt) 
  from   cte 
  where  cte.Id < (SELECT MAX(ID) FROM T1)
)
UPDATE T1
SET T1.Date = cte.dt
FROM T1 INNER JOIN cte ON T1.Id = cte.Id

Answer 6

您不能直接在更新查询中使用Windowed functions。您应该将逻辑存储在某些temporary table中，然后在更新查询中使用该值。一种方法可能如下所示。

 ;with cte as
    (
     select id,Invoice,dateadd(DAY, ROW_NUMBER() over (order by id), GetDate()) as dt
    from T1
    )
    update a
    set a.[date]= cte.dt
    from T1  a join cte on cte.id=a.id
    where a.id=cte.id

根据ID使用增量日期更新列

6 个答案: