Question

SELECT * FROM user_follow WHERE (post, "user", type, following)
IN ((25, 1, 'pc' || 'pl' || 'pf', true), (25, 2, 'pc' || 'cc'|| 'cl', true))

在第三列中，我想匹配“ pc”，“ pl”，“ pf”。我不相信我在使用正确的语法，因为我什么时候都没有得到结果，而且我也尝试使用OR而不是||。但它也不起作用。正确的方法是什么？

我仍然需要多个IN查询，它们要与内括号中的确切要求匹配

Answer 1

||进行字符串连接。

看起来像你想要的

SELECT * FROM user_follow
WHERE post=25
AND (
    ("user" = 1 AND type IN ('pc', 'pl', 'pf'))
    OR ("user" = 2 AND type IN ('pc', 'cc', 'cl'))
)
AND following=true

您还可以这样定义可能的组合：

with params(u, t) as values (
    (1, array['pc', 'pl', 'pf']),
    (2, array['pc', 'cc', 'cl'])
)
select "user".* from "user", params
where post=25
and "user"=u
and type=any(t)
and following=true

Answer 2

好吧，您始终可以使用普通的逻辑运算符来重写它，诸如此类...

SELECT
    *
FROM
    user_follow
WHERE
    (
        post = 25,
        AND "user" = 1
        AND type IN ('pc', 'pl', 'pf')
        AND = true
    )
    OR (
        post = 25,
        AND "user" = 2
        AND type IN ('pc', 'cc', 'cl')
        AND = true
    )

Answer 3

您可以如下查询：

SELECT *
  FROM user_follow
 WHERE ("user" IN ('pc', 'pl', 'pf') AND (post, type, following) IN ((25, 1, true)
     OR "user" IN ('pc', 'cc', 'cl') AND (post, type, following) IN ((25, 2, true));

让我知道它是否满足您的要求。

谢谢， Idrees

Postgresql如何使用IN进行多列文本匹配

3 个答案: