Question

这是我的数组：

           ['','','','','2,509','2.58 hrs / 1.20 days','38','7.78 
           hrs / 1.16 days','1.28','6.62 mins / 6.62 mins']

我想将整天，分钟转换为小时，该怎么办？

like [''，''，''，''，'2,509'，'2.58 hrs / 28.8 hrs'，'38'，'7.78 hrs / 27.84 hrs'，'1.28'，'0.110 hrs / 0.110 hrs']

Answer 1

import re

a =  ['','','','','2,509','2.58 hrs / 1.20 days','38','7.78 hrs / 1.16 days','1.28','6.62 mins / 6.62 mins']

def repl(x):
   n ={'days':'*24hrs','mins': '/60 hrs'}.get(x.group(2))
   n = '' if n is None else n
   s = '' if x.group(2) in['mins','days'] else 'hrs'
   return x.group(1)+s+n

re.sub(r'(\d\S+)\s([a-z]+)',repl,"\n".join(a)).split('\n')
['',
 '',
 '',
 '',
 '2,509',
 '2.58hrs / 1.20*24hrs',
 '38',
 '7.78hrs / 1.16*24hrs',
 '1.28',
 '6.62/60 hrs / 6.62/60 hrs']

尽管这是您解决方案的复制品，但是要先除还是先乘等意义不大。所以我想括号的介绍会很棒：

def repl(x):
   n ={'days':'*24 hrs','mins': '/60 hrs'}.get(x.group(2))
   n = '' if n is None else n
   if x.group(2)=='hrs': return x.group(1)+x.group(2) + n
   return f'({x.group(1)} {n})'       


re.sub(r'(\d\S+)\s([a-z]+)',repl,"\n".join(a)).split('\n')
Out[1211]: 
['',
 '',
 '',
 '',
 '2,509',
 '2.58hrs / (1.20*24 hrs)',
 '38',
 '7.78hrs / (1.16*24 hrs)',
 '1.28',
 '(6.62/60 hrs) / (6.62/60 hrs)']

如果您需要解决：

a =  ['','','','','2,509','2.58 hrs / 1.20 days','38','7.78 hrs / 1.16 days','1.28','6.62 mins / 6.62 mins']

def repl(x):
   n ={'days':'*24','mins': '/60'}.get(x.group(2))
   n = '' if n is None else n
   s = '' if x.group(2) in['mins','days'] else 'hrs'
   return str(round(eval(re.sub('[^0-9.]','',x.group(1))+n),4))+'hrs'

 re.sub(r'(\d\S+)\s([a-z]+)',repl,"\n".join(a)).split('\n')
['',
 '',
 '',
 '',
 '2,509',
 '2.58hrs / 28.8hrs',
 '38',
 '7.78hrs / 27.84hrs',
 '1.28',
 '0.1103hrs / 0.1103hrs']

在Python中将表示为“ 3.5天”的时间字符串转换为“ 3.5 * 24小时”

1 个答案: