Question

我正在尝试通过http从DVR读取多台摄像机，并且当我仅选择一个摄像机流时，我的代码可以正常工作。

Java2DFrameConverter conv = new Java2DFrameConverter();
        HttpURLConnection con = (HttpURLConnection) new URL("127.0.0.1").openConnection();
        con.setRequestMethod("GET");
        InputStream is = con.getInputStream();
        FFmpegFrameGrabber g = new FFmpegFrameGrabber(is);
        g.start();
        g.setFormat("h264");

        int read = 0;
        int fileNum = 0;
        while (true)
        {
            BufferedImage img = conv.convert(g.grabFrame());
            ImageIO.write(img, "png", new File("out" + (fileNum++) + ".png"));
        }

使用与上面类似的代码，我知道可以正常工作，并且可以正确解码流，我尝试写出两个摄像机的流，只是交替抓取帧并保存它们，但是，似乎无法正确解码，并且有很多“损坏？ ”如下图所示，以及原始的h264二进制流。

h264 stream of 2 cameras with "corruption?"

h264 binary stream of 2 cameras

ffmpeg报告以下流信息

Input #0, h264, from 'out.h264':
  Duration: N/A, bitrate: N/A
    Stream #0:0: Video: h264 (Baseline), yuv420p(progressive), 720x288, 25 fps, 25 tbr, 1200k tbn, 50 tbc



Java2DFrameConverter conv = new Java2DFrameConverter();
        HttpURLConnection con = (HttpURLConnection) new URL("127.0.0.1").openConnection();
        con.setRequestMethod("GET");
        InputStream is = con.getInputStream();
        FFmpegFrameGrabber g = new FFmpegFrameGrabber(is);
        g.setFormat("h264");
        g.start();

        int read = 0;
        int[] fileNum = new int[2];
        int cameras = 2;
        int camera = 0;
        while (true)
        {
            BufferedImage img = conv.convert(g.grabFrame());
            ImageIO.write(img, "png", new File("out" + (camera) + (fileNum[camera]++) + ".png"));
            camera++;
            if(camera >= cameras) camera = 0;
        }

这是流数据的问题还是我在解码流时缺少东西？

从DVR拆分h264流

0 个答案: