Question

我正在尝试显示显示1月至12月位置的每月计数的数据。

我编写了查询以从服务器获取必要的数据，但是当我在表的视图中显示查询时，数据的布局看起来并不像我希望的那样。我相信我必须先将在查询中编写的数组重建为正确的格式，然后才能在表中显示它？

现在，从服务器返回的数据看起来像这样

<table id="registeredTable" class="table table-striped table-bordered table-hover">
<thead>
    <tr>
        <th>Locations</th>
        <th>January</th>
        <th>Feburary</th>
        <th>March</th>
        <th>April</th>
        <th>May</th>
        <th>June</th>
        <th>July</th>
        <th>August</th>
        <th>September</th>
        <th>October</th>
        <th>November</th>
        <th>December</th>
    </tr>
</thead>
<tbody>
    <?php
      foreach($selectAllmonthlylocations as $item) {
        echo '
    <tr>
      <td>'.$item["locations"].'</td>
      <td>'.$item["Total"].'</td>
    </tr>
        ';
  }
    ?>
</tbody>
</table>

所以我的问题是如何正确格式化数组以按需要在表中显示？

这是我的代码：

$selectallmonthlysql = 'SELECT locations, DateAdded, COUNT(*) as Total
                    FROM testserverdataSignup
                    WHERE DateAdded > "2017-12-31"
                    GROUP BY month(DateAdded), locations';

    $selectAllmonthlystmt = $dbo->prepare($selectallmonthlysql);

    $selectAllmonthlystmt->execute();

    $selectAllmonthlylocations = $selectAllmonthlystmt->fetchAll(PDO::FETCH_ASSOC);

该表格当前的屏幕截图：我希望每个位置的个人计数与月份相关联，而不是向下

Answer 1

首先更改您的查询

$selectallmonthlysql = '
SELECT
    locations,
    MONTHNAME(DateAdded) AS month,
    COUNT(*) AS total
FROM    
    testserverdataSignup
WHERE
    DateAdded > "2017-12-31"
GROUP BY month(DateAdded),locations';

我将Total小写为total，这使我很恼火。

使用PDO，您可以

$results = $selectAllmonthlystmt->fetchAll(PDO::FETCH_GROUP);
foreach($results AS $location => $row ){

FETCH_GROUP的文献资料很少，但这会以第一列作为嵌套数组的Key来组织数据，在这种情况下，正是我们想要的位置。我使用PDO而不是我不会提及的其他数据库库的原因之一，但它以MySql开头并以i结尾。

MONTHNAME（单击获取文档）将返回月份的全名，例如“ February”，尽管这不是必需的（只是一个数字就可以了），但在输出数组进行调试时更容易阅读。 / p>

您将得到类似这样的东西

//canned example data, notice one month is out of order and the big gap
// between February to October, this is to show it properly orders and
//fills those in. Always best to test this situations.
$result = array(
   "Austin_Domestic" => array(

       0 => Array(
            "month" => "February",
            "total" => 5
        ),
       1 => Array(
            "month" => "January",
            "total" => 15
        ),
        2 => Array(
            "month" => "October",
            "total" => 8
        ),

    ),
);
//$results = $selectAllmonthlystmt->fetchAll(PDO::FETCH_GROUP);

//then putting it all together

//we'll need the months in an array anyway so we can saves some space with them in the HTML  too.
$months = array(    
    "January",
    "February",
    "March",
    "April",
    "May",
    "June",
    "July",
    "August",
    "September",
    "October",
    "November",
    "December"
)

?>

<table id="registeredTable" class="table table-striped table-bordered table-hover">
<thead>
    <tr>
        <th>Locations</th>
        <?php foreach($months as $month){
             //Output the names of the months
             echo "<th>{$month}</th>\n";
        } ?>
        </tr>
    </thead>
    <tbody>
    <?php 
        foreach( $result as $location => $rows ){
             echo "<tr>\n";
             echo "<td>{$location}</td>\n";
            //simplifies lookup by month (indexes are correlated)
            //it returns column 'month' from $rows as a flat array.
            //we can save ourselves an external loop by doing this "trick"
            $m = array_column($rows, 'month');
            //for example, in the case: [0=>February,1=>January,2=>October]
            //because this is created from $rows, with a natural number index
            //we can simply do array_search on $m to get the index we need in $rows (see below)
            foreach($months as $month){
                $index = array_search($month, $m);
                if(false === $index){
                    echo "<td>0</td>\n";
                }else{
                   echo "<td>{$rows[$index]['total']}</td>\n"; 
                }                 
            }
            echo "</tr>\n";
        }
    ?>
    </tbody>
</table>

输出（我确实对其进行了格式化，以使其看起来更好）：

<table id="registeredTable" class="table table-striped table-bordered table-hover">
    <thead>
        <tr>
            <th>Locations</th>
            <th>January</th>
            <th>February</th>
            <th>March</th>
            <th>April</th>
            <th>May</th>
            <th>June</th>
            <th>July</th>
            <th>August</th>
            <th>September</th>
            <th>October</th>
            <th>November</th>
            <th>December</th>
        </tr>
    </thead>
    <tbody>
        <tr>
            <td>Austin_Domestic</td>
            <td>15</td>
            <td>5</td>
            <td>0</td>
            <td>0</td>
            <td>0</td>
            <td>0</td>
            <td>0</td>
            <td>0</td>
            <td>0</td>
            <td>8</td>
            <td>0</td>
            <td>0</td>
        </tr>
    </tbody>
</table>

Sandbox

几个月来使用数组的一个好处是，您拼写为Feburary错了，应该是February，这是我已经犯了很多次罪了。

唯一真正的缺点是月份名称必须与从数据库返回的月份名称相匹配，如果拼写正确（这是我发现错误的方式），这应该不是问题。否则，同样的想法可以很容易地应用到月份中。

干杯！

Answer 2

首先，您应该更改查询以返回MONTH(DateAdded)而不是整个日期，因为这是输出表的组织方式：

$selectallmonthlysql = 'SELECT locations, MONTH(DateAdded) AS month, COUNT(*) as Total
                FROM testserverdataSignup
                WHERE DateAdded > "2017-12-31"
                GROUP BY month, locations';

然后，您应该将数组重组为嵌套数组：

array(location1 => array(month1 => total1, month2 => total2, ...),
      location2 => array(month1 => total1, month2 => total2, ...),
      ...)

此代码将执行以下操作：

$groupedData = array();
while ($selectAllmonthlystmt->fetch(PDO::FETCH_ASSOC) {
    $groupedData[$row['locations']][$row['month']] = $row['Total'];
}

然后，您可以在创建表时使用嵌套循环。外层循环创建行，内层循环用于行中的单元格。

foreach ($groupedData as $location => $locationData) {
    echo "<tr><td>$location</td>";
    for ($month = 1; $month <= 12; $month++) {
        echo "<td>";
        echo isset($locationData[$month]) ? $locaitonData[$month] : 0;
        echo "</td>";
    }
    echo "</tr>";
}

重建PHP数组以正确地将数据放入html表中

2 个答案: