Question

我正在尝试在结果中创建一个新列，该列由“ PrimaryName”的前3个字符，所有“ VendorCity”和“ VendorZip”的前5个字符组成

SELECT,VendorName
      ,replace(PrimaryVendorLocationName,' ','') as PrimaryName
      ,replace(PrimaryVendorLocationCity,' ','') as VendorCity
      ,replace(PrimaryVendorLocationZipCode,' ','') as VendorZip
FROM [table]

如您所见，我还需要删除空格以确保更干净的返回。我想将新列称为“ NewVendorCode”。因此，记录是这样产生的：

R A Slack
Chicago Heights
60654-1234

将返回此：

RASChicagoHeights60654

Answer 1

您可以使用LEFT（MySQL / TSQL）使用以下内容：

SELECT CONCAT(
    LEFT(REPLACE(PrimaryVendorLocationName, ' ', ''), 3),
    REPLACE(PrimaryVendorLocationCity, ' ', ''),
    LEFT(REPLACE(PrimaryVendorLocationZipCode, ' ', ''), 5)
) FROM table_name

...或者您可以使用SUBSTRING（MySQL / TSQL）（而不是LEFT）：

SELECT CONCAT(
    SUBSTRING(REPLACE(PrimaryVendorLocationName, ' ', ''), 1, 3),
    REPLACE(PrimaryVendorLocationCity, ' ', ''),
    SUBSTRING(REPLACE(PrimaryVendorLocationZipCode, ' ', ''), 1, 5)
) FROM table_name

注意：如您所见，SELECT查询可在MySQL和TSQL上正常运行。

演示（MySQL）： https://www.db-fiddle.com/f/wTuKzosFgkEuKXtruCTCxg/0
演示（TSQL）： http://sqlfiddle.com/#!18/dbc98/1/1

Answer 2

您可以使用以下代码：

  SELECT VendorName+
  replace(PrimaryVendorLocationName,' ','') +
  replace(PrimaryVendorLocationCity,' ','') +
  replace(PrimaryVendorLocationZipCode,' ','') as NewVendorCode

Answer 3

SELECT VendorName
  ,PrimaryName
  ,VendorCity
  ,VendorZip
  ,CONCAT(LEFT(PrimaryName,3),VendorCity,LEFT(VendorZip,5)) As NewVendorCode
FROM (
     SELECT VendorName
       ,replace(PrimaryVendorLocationName,' ','') as PrimaryName
       ,replace(PrimaryVendorLocationCity,' ','') as VendorCity
       ,replace(PrimaryVendorLocationZipCode,' ','') as VendorZip
     FROM [table]
)

如何将三列的一部分合并为一个新列

3 个答案: