如何使用变量使用python-barcode生成条形码

时间:2018-08-13 16:31:10

标签: python barcode

我正在尝试使用python-barcode(https://github.com/WhyNotHugo/python-barcode)生成条形码。我设法像这样生成并保存为png的条形码:

import barcode
from barcode.writer import ImageWriter

EAN = barcode.get_barcode_class('ean13')
ean = EAN(u'5901234123457', writer=ImageWriter())
fullname = ean.save('barcode')

但是,如果我尝试使用变量中的值,则无法使用:

import barcode
from barcode.writer import ImageWriter

number = 5901234123457    

EAN = barcode.get_barcode_class('ean13')
ean = EAN(number, writer=ImageWriter())
fullname = ean.save('barcode')

然后我得到

TypeError: 'int' object is not subscriptable

我可能犯了一些愚蠢的错误,但是我对此很陌生...:/

2 个答案:

答案 0 :(得分:4)

条形码模块仅接受字符串作为输入,然后应将该整数设为字符串:

import barcode
from barcode.writer import ImageWriter

number = 5901234123457 
number = str(number)

EAN = barcode.get_barcode_class('ean13')
ean = EAN(number, writer=ImageWriter())
fullname = ean.save('barcode')

答案 1 :(得分:0)

from processing import *
from random import randint


def decimalToBinary(x):
    #This function converts a Decimal into a Binary
    #It generates a nibble (4 digits binary number)
    binaryNumber=bin(x)[2:]
    return (4-len(binaryNumber)) * "0" + binaryNumber

def drawBarCode(height): 
    #Generates a 13-digit bar code.
    marginLeft=30
    marginTop=40
    for i in range(1,14):  
        digit=randint(0,9)
        nibble=decimalToBinary(digit)
        for j in range(0,4):  
            if nibble[j:j+1]=="1":
                fill(0,0,0)
                stroke(0,0,0)
            else:
                fill(255,255,255)
                stroke(255,255,255)
            rect(marginLeft+i*8+2*j, marginTop, 2, height)

        #Display the digit in Decimal
        fill(0,0,0)
        stroke(0,0,0)
        #textSize(10)
        text(digit,marginLeft+i*8,marginTop+20+height)


def setup():
    strokeWeight(12)
    size(200,200)
    background(255,255,255)
    fill(0,0,0)
    stroke(0,0,0)
    drawBarCode(80)

run()